Question

是否有一种很好的方法可以为_.debounce获得类似的行为，但区别在于每个更改的参数都执行一次？例如：

foo = function (arg) {console.log(arg)}
lazy = _.debounce(foo,1000)

lazy("a")
lazy("a")
lazy("a")
lazy("a")
lazy("b")
a // with debounce "a" would not be printed
b // but i would like run the debounced function once for every changed arg.

Answer 1

由于缺乏更好的解决方案，我想出了这个：

args = {}
function markAllAsUnread(rooms) {
    _.each(rooms,function (roomname) {
        // Here i do my heavy work....
        console.log(roomname)
    })
    args = {}
}

markAllAsUnreadLazy = _.debounce(markAllAsUnread,2000)

function markAsUnread (arg) {
    args[arg] = arg // to unify the given args
    markAllAsUnreadLazy(args)
}


markAsUnread (1)
markAsUnread (1)
markAsUnread (123)
markAsUnread (123123)
markAsUnread (123123)
markAsUnread (123123)
markAsUnread (12334)

1
123
12334
123123

针对每个不同的论点进行下划线辩护

1 个答案: