我必须从两个列表中返回XML,如下面的格式
TABLE
month count
----- ----
January 578
February 300
March 147
April 45
May 8
XML
<January>578</January>
<February>300</February>
<March>147</March>
<April>45</April>
<May>8</May>
我尝试过以下SQL语句,
SELECT * FROM #temp;
SELECT (
SELECT monthId AS 'month/@atr', count AS month
FROM #temp
FOR XML PATH(''), TYPE
)
FOR XML PATH('')
我知道上面的脚本用于获取第一列值作为属性。 在我的例子中,我需要第一列值作为节点,第二列作为其值。
感谢您的帮助。
答案 0 :(得分:4)
DECLARE @t TABLE ([month] VARCHAR(50) PRIMARY KEY, [count] INT)
INSERT INTO @t
VALUES
('January', 578), ('February', 300),
('March', 147), ('April', 45), ('May', 8)
SELECT *
FROM @t
PIVOT (
SUM(count)
FOR month IN ([January], [February], [March], [April], [May], [June], [Jule])
) p
FOR XML PATH('')
答案 1 :(得分:4)
在直接的方式上,您可以(可能)使用pivot或使用动态SQL:
DECLARE @tbl TABLE([month] VARCHAR(100),[count] INT);
INSERT INTO @tbl VALUES
('January',578)
,('February',300)
,('March',147)
,('April',45)
,('May',8);
DECLARE @cmd VARCHAR(MAX)=
'SELECT ' +
(
STUFF(
(
SELECT ',' + CAST(tbl.[count] AS VARCHAR(100)) + ' AS [' + tbl.[month] + ']'
FROM @tbl AS tbl
FOR XML PATH('')
),1,1,''
)
)
+
' FOR XML PATH('''');';
EXEC(@cmd);
结果
<January>578</January>
<February>300</February>
<March>147</March>
<April>45</April>
<May>8</May>
更好(更容易查询!)来创建这样的结构:
SELECT tbl.[month] AS [@name]
,tbl.[count] AS [*]
FROM @tbl AS tbl
FOR XML PATH('month');
结果
<month name="January">578</month>
<month name="February">300</month>
<month name="March">147</month>
<month name="April">45</month>
<month name="May">8</month>
答案 2 :(得分:4)
奇怪,但服务于目的,
DECLARE @MyTable TABLE ( Month VARCHAR(20), Count INT)
INSERT INTO @MyTable (Month, Count)
VALUES
('January' , 578)
,('February', 300)
,('March' , 147)
,('April' , 45 )
,('May' , 8 )
SELECT
CAST('<' + Month + '>' + CAST(Count AS VARCHAR(20)) + '</' + Month + '>' AS XML)
FROM @MyTable
FOR XML PATH('')
----输出----
<January>578</January>
<February>300</February>
<March>147</March>
<April>45</April>
<May>8</May>