Question

我尝试以下操作，但未应用LIKE过滤器，即它返回完整的结果集。有什么想法吗？正如您在下面的日志中看到的那样，LIKE标准就在那里，但我猜这些参数没有填充。

    CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
    CriteriaQuery<T> criteriaQuery = criteriaBuilder.createQuery(typeParameterClass);

    // from
    Root<T> from = criteriaQuery.from(typeParameterClass);
    criteriaQuery.select(from);

    // like
    if (searchQuery != null && searchQuery.trim().length() > 0) {
        List<Predicate> predicates = new ArrayList<Predicate>();
        for (String name : getColumnNames(typeParameterClass)) {
            Predicate condition = criteriaBuilder.like(from.<String>get(name), "%" + searchQuery + "%");
            predicates.add(condition);
        }
        criteriaQuery.where(criteriaBuilder.or(predicates.toArray(new Predicate[] {})));
    }

    List<T> results = (List<T>) entityManager.createQuery(criteriaQuery).setFirstResult(firstResult)
            .setMaxResults(maxResults).getResultList();
    return results;

日志：

select
employee0_.id as id1_1_,
employee0_.AVATAR as AVATAR2_1_,
employee0_.AVERAGE_RATING as AVERAGE_3_1_,
employee0_.DISTANCE as DISTANCE4_1_,
employee0_.DRIVERS_LICENCE as DRIVERS_5_1_,
employee0_.EMAIL_ADDRESS as EMAIL_AD6_1_,
employee0_.FIRST_NAME as FIRST_NA7_1_,
employee0_.JOB_DESCRIPTION as JOB_DESC8_1_,
employee0_.JOB_DETAILS as JOB_DETA9_1_,
employee0_.JOB_TITLE as JOB_TIT10_1_,
employee0_.JOINING_DATE as JOINING11_1_,
employee0_.LASTACCESS_DATE as LASTACC12_1_,
employee0_.LAST_NAME as LAST_NA13_1_,
employee0_.MOBILE_NUMBER as MOBILE_14_1_,
employee0_.PASSWORD as PASSWOR15_1_,
employee0_.PHONE_NUMBER as PHONE_N16_1_,
employee0_.SALARY as SALARY17_1_,
employee0_.SALARY_TIMEFRAME as SALARY_18_1_,
employee0_.SEX as SEX19_1_,
employee0_.USERNAME as USERNAM20_1_,
employee0_.WORK_LAT1 as WORK_LA21_1_,
employee0_.WORK_LAT2 as WORK_LA22_1_,
employee0_.WORK_LAT3 as WORK_LA23_1_,
employee0_.WORK_LAT4 as WORK_LA24_1_,
employee0_.WORK_LAT5 as WORK_LA25_1_,
employee0_.WORK_LONG1 as WORK_LO26_1_,
employee0_.WORK_LONG2 as WORK_LO27_1_,
employee0_.WORK_LONG3 as WORK_LO28_1_,
employee0_.WORK_LONG4 as WORK_LO29_1_,
employee0_.WORK_LONG5 as WORK_LO30_1_ 
11:36:53,974 INFO  [stdout] (default task-2)     from
employee employee0_ 
11:36:53,974 INFO  [stdout] (default task-2)     where
employee0_.FIRST_NAME like ? 
or employee0_.LAST_NAME like ? 
or employee0_.PASSWORD like ? 
or employee0_.EMAIL_ADDRESS like ? 
or employee0_.PHONE_NUMBER like ? 
or employee0_.MOBILE_NUMBER like ? 
or employee0_.JOB_TITLE like ? 
or employee0_.JOB_DESCRIPTION like ? 
or employee0_.USERNAME like ? 
or employee0_.JOB_DETAILS like ?

Answer 1

试试这个：

CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery<T> criteriaQuery = criteriaBuilder.createQuery(typeParameterClass);

// from
Root<T> from = criteriaQuery.from(typeParameterClass);
criteriaQuery.select(from);

// like
if (searchQuery != null && searchQuery.trim().length() > 0) {
    List<Predicate> predicates = new ArrayList<Predicate>();
    for (String name : getColumnNames(typeParameterClass)) {
     //comparing same case name
        Predicate condition = criteriaBuilder.like(criteriaBuilder.upper(from.<String>get(name)), "%" + searchQuery.toUpperCase() + "%");
        predicates.add(condition);
    }

    //criteriaQuery.where(criteriaBuilder.or(predicates.toArray(new Predicate[] {})));

    Predicate[] predicatesArr = new Predicate[predicates.size()];
    predicates.toArray(predicatesArr);
    query.where(predicatesArr);
}

List<T> results = (List<T>) entityManager.createQuery(criteriaQuery).setFirstResult(firstResult)
        .setMaxResults(maxResults).getResultList();
return results;

建议在搜索时始终使用相同的案例。

JPA Like Clause不起作用

1 个答案: