Question

我在每个用户的排名方面都有问题是完美的，问题是当用户＆＃34; a＆＃34;与用户＆＃34; b＆＃34;

具有相同的结果

我的代码

  SELECT ID, Wins, 
    (SELECT COUNT(*)+1 FROM users WHERE Wins>x.Wins) AS rank_upper, 
    (SELECT COUNT(*) FROM users WHERE Wins>=x.Wins) AS rank_lower 
 FROM `users` x WHERE x.username='$_GET[user]'

ID   wins Rank
 1    23    1
 2    17    2
 3    17    2
 4    10    3
 5    10    3

我喜欢这样：

 ID   wins Rank
 1    23    1
 2    17    2
 3    17    3
 4    10    4
 5    10    5

Answer 1

比较id也可能对您有用

SELECT ID, Wins, 
    (SELECT COUNT(*)+1 FROM users WHERE Wins>x.Wins or (Wins=x.Wins and id<x.id)) AS Rank 
 FROM `users` x WHERE x.username='$_GET[user]'

mysql - 赢得排名没有平局

1 个答案: