Question

我有三个输入，分别是日，月和年。

<div id="birthday">
    <div>
        <label for="day">Day</label>
        <input type="number" id="day" placeholder="Day" name="day" ref="day" />
    </div>
    <div>
        <label for="month">Month</label>
        <input type="number" id="month" placeholder="Month" name="month" ref="month" />
    </div>
    <div>
        <label for="year">Year</label>
        <input type="number" id="year" placeholder="Year" name="year" ref="year" />
    </div>
    <span class="clear_both"></span>
</div>

我想通过以下方式验证日期：

年
- 年份应该有4个字符（即YYYY）
- 年份应在1900年至今年之间。
月
- 月份应在1到12之间
天
- 如果年份为闰年，则月份为2月（2月），则日期应为1至29
- 如果年份不是闰年，则该日期应介于1至31或1至30之间，具体取决于月份

我只能查看月份和年份：

let day = this.refs.day.value
let month = this.refs.month.value
let year = this.refs.year.value
let errors = []

if (!((year.length == 4) && (year > 1900 && year < 2016))) {
    errors.push("year");
}
if (!(month > 0 && month < 13)) {
    errors.push("month");
}

如何在javascript中完成此工作？请你帮助我好吗。谢谢。

Answer 1

这可能会对你有帮助。

function daysInMonth(m, y) { // Month is indexed as 0-11
    switch (m) {
        case 1 :
            return (y % 4 === 0 && y % 100) || y % 400 === 0 ? 29 : 28;
        case 8 : case 3 : case 5 : case 10 :
            return 30;
        default :
            return 31
    }
}

function isValid(d, m, y) {
    return m >= 0 && m < 12 && d > 0 && d <= daysInMonth(m, y);
}

Answer 2

在这里回答我自己的问题。安德里亚的回答向我指出了正确的方向。虽然有一个错误，我在这个答案中清除了。错误是，如果月份大于let day = this.refs.day.value let month = this.refs.month.value let year = this.refs.year.value var monthLength = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ]; var total_days = 0; // Adjust for leap years if(year % 400 == 0 || (year % 100 != 0 && year % 4 == 0)) monthLength[1] = 29; let errors = [] console.log('total_days = ' + total_days); if (!((year.length == 4) && (year > 1900 && year < 2016))) { errors.push("year"); } if (!(month > 0 && month < 13)) { errors.push("month"); total_days = monthLength[0]; } else { total_days = monthLength[month - 1]; } if (!(day > 0 && day <= total_days)) { errors.push("day"); }中的项目列表，那么这将是错误的一天。还更改为检查所选月份的天数是否在1到总天之间。所以这是完整的脚本：

<table id="example" class="table table-striped table-bordered" cellspacing="0" width="100%">
<thead>
    <tr>
        <th>ID</th>
        <th>Message Type</th>
        <th>Crime Type</th>
        <th>Description</th>
        <th>Date/Time Reported</th>
        <th>Date/Time Committed</th>
        <th>Sender</th>
        <th>Status</th>
        <th>Options</th>
    </tr>
</thead>
<tfoot>
    <tr>
        <th>--</th>
        <th>--</th>
        <th>--</th>
        <th>--</th>
        <th>--</th>
        <th>--</th>
        <th>--</th>
        <th>--</th>
    </tr>
</tfoot>
<tbody>
<?php
$query = "SELECT reports.id, types.`name`, classifications.`name` as class, reports.description,
concat(DATE_FORMAT(reports.committed_at,'%b %e, %Y'), ' at ', TIME_FORMAT(reports.committed_at,'%l:%i:%p')) as committed_at,
concat(DATE_FORMAT(reports.created_at,'%b %e, %Y'), ' at ', TIME_FORMAT(reports.created_at,'%l:%i:%p')) as created_at,
reports.casestat, users.`name` as sender, concat(status.id, ' - ', status.status) as status FROM reports
INNER JOIN types ON reports.type_id = types.id
INNER JOIN classifications ON reports.classification_id = classifications.id
INNER JOIN users ON reports.created_by = users.id
INNER JOIN status ON reports.casestat = status.id"; 

$result = mysql_query($query);
    while($row = mysql_fetch_array($result))
      {
          switch($row['casestat']){

              case 0: $rwcol="#ff3c3c"; break; 
              case 1: $rwcol="#ffb93c"; break;
              case 2:$rwcol="#ffff3c"; break;
              case 3: $rwcol="#00bc00"; break;
              case 4: $rwcol="#5a5aff"; break;
               }                  
      echo "<tr bgcolor=$rwcol>";
      echo "<td id='code'>" . $row['id'] . "</td>";
      echo "<td>" . $row['name'] . "</td>";
      echo "<td>" . $row['class'] . "</td>";
      echo "<td>" . $row['description'] . "</td>";
      echo "<td>" . $row['created_at'] . "</td>";
      echo "<td>" . $row['committed_at'] . "</td>";
      echo "<td>" . $row['sender'] . "</td>";
      echo "<td>" . $row['status'] . "</td>";
      echo "<td><a onclick='updateStat(this.id)' id='".$row['id']."' href='#' ><abbr title='Edit'><i class='fa fa-edit'></i></abbr>Update Status</a> </tr>";}
?>

</tbody>

Answer 3

类似于user3817980，并且基于此question但内置于您的代码中，请参阅下文。

我也在检查这一天是不是消极的，这可能是一种过度杀伤但不会造成伤害。

let day = this.refs.day.value
let month = this.refs.month.value
let year = this.refs.year.value
var monthLength = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 ];

// Adjust for leap years
if(year % 400 == 0 || (year % 100 != 0 && year % 4 == 0))
    monthLength[1] = 29;

let errors = []

if (!((year.length == 4) && (year > 1900 && year < 2016))) {
    errors.push("year");
}

if (!(month > 0 && month < 13)) {
    errors.push("month");
}

if (day < 0 || day > monthLength[month - 1]) {
    errors.push("day");
}

按日，月和年检查有效日期

3 个答案: