<table border="true">
<tr>
<th style="width:100px">Table</th>
<th colspan="3" style="width:300px">Columns</th>
</tr>
<tr>
<td style="width:100px">Articles</td>
<td style="width:100px">id</td>
<td colspan="2" style="width:200px; color: #aaaaaa">other dependent variables</td>
</tr>
<tr>
<td style="width:100px">Article_Tag</td>
<td style="width:100px">id</td>
<td style="width:100px">article_id</td>
<td style="width:100px">tag_id</td>
</tr>
<tr>
<td style="width:100px">Tags</td>
<td style="width:100px">id</td>
<td style="width:100px">name</td>
<td style="width:100px"></td>
</tr>
</table>
然后,我想按标签表的[名称]对文章表进行排序。 我尝试用下面的封口加载,但它没有用。 模型文章和标签只是由belongsToMany相互连接, 我成功输出了他们的数据,但是他们没有排序。事实上,我没有给getTag任何论据。(当我给出论证时,他们也没有被[名字]缩小。)
use App\Article;
use App\Tag;
...
public function __construct(Article $article)
{
$this->article = $article;
}
...
public function getTag($tag = NULL)
{
$flag = isset($tag);
$articles = $this->article->orderBy('created_at', 'desc')->with([
'tags' => function($query) use ($flag, $tag){
($flag)
? $query->where('name', $tag)
: $query->orderBy('name');
}
])->paginate(15);
答案 0 :(得分:0)
尝试此变体:
$articles = $this->article->with([
'tags' => function($query) use ($flag, $tag){
return $flag
? $query->where("name", $tag);
: $query->orderBy("name")
}
])->paginate(15);