在我的Google Search API调用中,它返回一个有效的JSON,但每当我解析它以获取特定值时,我都会得到Undefined

时间:2016-07-25 02:45:18

标签: javascript json

这是我从简单的Google Api Search中收集的JSON 我想获得第一个Url(https://www.facebook.com/Rashtriye-Goraksha-Sena-Appeal-Pls-Save-Mother-Cow-149271605156819/) 不要问我为什么这是牛的第一个链接lol

{
 "kind": "customsearch#search",
 "url": {
  "type": "application/json",
  "template": "https://www.googleapis.com/customsearch/v1?q={searchTerms}&num={count?}&start={startIndex?}&lr={language?}&safe={safe?}&cx={cx?}&cref={cref?}&sort={sort?}&filter={filter?}&gl={gl?}&cr={cr?}&googlehost={googleHost?}&c2coff={disableCnTwTranslation?}&hq={hq?}&hl={hl?}&siteSearch={siteSearch?}&siteSearchFilter={siteSearchFilter?}&exactTerms={exactTerms?}&excludeTerms={excludeTerms?}&linkSite={linkSite?}&orTerms={orTerms?}&relatedSite={relatedSite?}&dateRestrict={dateRestrict?}&lowRange={lowRange?}&highRange={highRange?}&searchType={searchType}&fileType={fileType?}&rights={rights?}&imgSize={imgSize?}&imgType={imgType?}&imgColorType={imgColorType?}&imgDominantColor={imgDominantColor?}&alt=json"
 },
 "queries": {
  "request": [
   {
    "title": "Google Custom Search - cow pls",
    "totalResults": "315000",
    "searchTerms": "cow pls",
    "count": 10,
    "startIndex": 1,
    "inputEncoding": "utf8",
    "outputEncoding": "utf8",
    "safe": "off",
    "cx": "002141288598133749978:zrk0yz6qoee"
   }
  ],
  "nextPage": [
   {
    "title": "Google Custom Search - cow pls",
    "totalResults": "315000",
    "searchTerms": "cow pls",
    "count": 10,
    "startIndex": 11,
    "inputEncoding": "utf8",
    "outputEncoding": "utf8",
    "safe": "off",
    "cx": "002141288598133749978:zrk0yz6qoee"
   }
  ]
 },
 "context": {
  "title": "Web"
 },
 "searchInformation": {
  "searchTime": 0.379396,
  "formattedSearchTime": "0.38",
  "totalResults": "315000",
  "formattedTotalResults": "315,000"
 },
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   "kind": "customsearch#result",
   "title": "Rashtriye Goraksha Sena Appeal Pls Save Mother Cow",
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   "displayLink": "www.facebook.com",
   "snippet": "Rashtriye Goraksha Sena Appeal Pls Save Mother Cow. 724 likes · 2 talking \nabout this. SAVE THE MOTHER COW.",
   "htmlSnippet": "Rashtriye Goraksha Sena Appeal \u003cb\u003ePls\u003c/b\u003e Save Mother \u003cb\u003eCow\u003c/b\u003e. 724 likes · 2 talking \u003cbr\u003e\nabout this. SAVE THE MOTHER \u003cb\u003eCOW\u003c/b\u003e.",
   "cacheId": "Pohw6X7G3PkJ",
   "formattedUrl": "https://www.facebook.com/Rashtriye-Goraksha-Sena-Appeal-Pls-Save- Mother-Cow-149271605156819/",
   "htmlFormattedUrl": "https://www.facebook.com/Rashtriye-Goraksha-Sena-Appeal-\u003cb\u003ePls\u003c/b\u003e-Save- Mother-\u003cb\u003eCow\u003c/b\u003e-149271605156819/",
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   "formattedUrl": "https://www.youtube.com/watch?v=qU_rdIkbZps",
   "htmlFormattedUrl": "https://www.youtube.com/watch?v=qU_rdIkbZps",
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}

使用以下代码

result=JSON.parse(body);
callback(result);
console.log(result);

它将返回给我一个有效的JSON 我得到了前面提到的JSON,一切运作良好

不幸的是,我不想要JSON ...我只想要第一个网址

我试过

console.log(result.items.link)
console.log(result.items.0.link)
console.log(result.items."0".link)

这些版本都不起作用。 我的Json解析器错了吗?

1 个答案:

答案 0 :(得分:1)

你想做

result.items[0].link

result.items是一个数组。要访问数组的第一个元素,必须使用方括号。