Question

`

$errormsg

你可以看看我的代码有什么问题吗？当用户名或密码错误时

<body>
<div class="layout">
    <div class="layout-screen">
        <div class="app-title">
            <h1>Login</h1>
        </div>

        <div class="layout-form">

            <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">

            <div class="control-group">
            <input type="text" name="username" class="login-field" value="" placeholder="username" id="login-username">
            <label class="login-field-icon fui-user" for="login-username"></label>
            </div>

            <div class="control-group">
            <span><?php if (isset($username_error)) { echo $username_error; } ?></span>
            </div>

            <div class="control-group">
            <input type="password" name="password" class="login-field" value="" placeholder="password" id="login-pass">
            <label class="login-field-icon fui-lock" for="login-pass"></label>
            </div>

            <div class="control-group">
            <span><?php if (isset($password_error)) { echo $password_error; } ?></span>
            </div>

            <div class="control-group">
            <input class="btn btn-primary btn-large btn-block" type="submit" name="login" value="Sign in"/>
            </div>

            </form>

            <span><?php if (isset($errormsg)) { echo $errormsg; } ?></span>

            <a class="layout-link" href="forgot.php">Lost your password?</a>

        </div>
    </div>
</div>

没有显示..

`

def bf: Int => Int => Int = i => v => i + v

Answer 1

问题是您的错误消息在此块

中

if ($row = mysqli_fetch_array($result)){
    if ($row['id'] == 1) {...} 
    else if ($row['id'] >= 1) {...} 
    else {
        $errormsg = "Incorrect username or Password!";
    }
}

这意味着永远不会显示错误消息，因为行ID始终为1或>=1。要解决此问题，请将错误消息移出，如下所示：

if ($row = mysqli_fetch_array($result)){
    if ($row['id'] == 1) {...} 
    else($row['id'] >= 1) {...}         
}
else {
    $errormsg = "Incorrect username or Password!";
}

elseif not working message不显示

1 个答案: