Question

我让Haversine工作，检索符合距离标准的行，但无法使Mysql COUNT（）函数正常工作。这是我的代码的一部分：

$query1 = "
SELECT COUNT(\"$table.*\") AS numrows1, outcodepostcodes.lat, outcodepostcodes.lng
,111.045* DEGREES(ACOS(COS(RADIANS($latpoint))
             * COS(RADIANS(outcodepostcodes.lat))
             * COS(RADIANS($longpoint) - RADIANS(outcodepostcodes.lng))
            + SIN(RADIANS($latpoint))
             * SIN(RADIANS(outcodepostcodes.lat)))) AS distance
FROM $table
LEFT JOIN outcodepostcodes
ON UPPER(\"$table.postcode\")=outcodepostcodes.outcode
HAVING ROUND(distance,2) <= $choosedistn
ORDER BY rent $reihenach LIMIT $offset, $rowsPerPage
";

然后按以下方式处理$查询：

$result1  = mysql_query($query1) or die('Error, query1 failed:' .mysql_error());
$result2  = mysql_query($query2) or die('Error, query2 failed:' .mysql_error());
$row1     = mysql_fetch_array($result1, MYSQL_ASSOC);
$row2     = mysql_fetch_array($result2, MYSQL_ASSOC);
$numrows1 = $row1['numrows1'];
$numrows2 = $row2['numrows2'];

我为$ numrows获取NULL。非常感谢任何帮助。

Answer 1

此处的引号错误COUNT(\"$table.*\") AS numrows1。

像这样做

COUNT(`$table`.*) AS numrows1

在Mysql中使用Haversine计算时，无法使COUNT（）工作

1 个答案: