Question

我正在学习Java。我能够建立一个简单的篮球记分员应用程序，现在并试图弄清楚如何建立一个网球记分牌。

一旦A组比赛达到6分，我无法弄清楚如何更新第2组A组的值。一旦A队比赛达到6，它就会更新第1组

这是代码

 Increase points on Team A */
public void incrementA(View view) {
    pointsTeamA = pointsTeamA + 1;
        {
            if (pointsTeamA == 1) displayA(15);
            if (pointsTeamA == 2) displayA(30);
            if (pointsTeamA == 3) displayA(40);
            if (pointsTeamA == 4) displayGamesA(gameTeamA = gameTeamA + 1);
            if (pointsTeamA == 4) displayA(pointsTeamA = 0);
            if (gameTeamA == 6) displaySet1A(gameTeamA);
            if (gameTeamA == 6) displayGamesA(gameTeamA = 0);
            if (gameTeamA == 6) displaySet2A(gameTeamA);
            if (gameTeamA == 6) displayGamesA(gameTeamA = 0);
        }
}

到目前为止，我的方法是：

    /*This method displays points for Team A. */
    private void displayA(int number) { TextView quantityTextView = (TextView) findViewById( R.id.points_team_A);
        quantityTextView.setText("" + number); }

    /*This method displays games for Team A */
    private void displayGamesA(int number) { TextView quantityTextView = (TextView) findViewById( R.id.game_score_team_A);
        quantityTextView.setText("" + number); }


    /*This method displays Set 1 for Team A */
    private void displaySet1A(int number) { TextView quantityTextView = (TextView) findViewById( R.id.set_1_team_A);
        quantityTextView.setText("" + number); }

    /*This method displays Set 2 for Team A */
    private void displaySet2A(int number) { TextView quantityTextView = (TextView) findViewById( R.id.set_2_team_A);
        quantityTextView.setText("" + number); }
}

任何帮助将不胜感激。

我将int的所有值设置为零，例如int gameTeamA = 0;

项目的最后一部分： 目标：当两位玩家的得分均为40时，它会显示＆＃34; Deuce＆＃34;然后为了让玩家A获胜，它必须连续得2分，其中第1点将显示＆＃34; ADV＆＃34;并且第2点将结束游戏，为gameTeamA添加一个分数并开始新游戏。

到目前为止

代码：

public void incrementA(View view) {
    pointsTeamA++;
    displayDeuceA(null);
    if (pointsTeamA == 1) displayA(15);
    if (pointsTeamA == 2) displayA(30);
    if (pointsTeamA == 3) displayA(40);
    if (pointsTeamA == 3 && pointsTeamB == 3)
        displayDeuceA("Deuce");
    if (pointsTeamA == 4) {
        displayGamesA(gameTeamA = gameTeamA + 1);
        displayA(pointsTeamA = 0);
        displayB(pointsTeamB = 0);
        displayDeuceA(null);
        displayDeuceB(null);
    }

Answer 1

创建多行If语句可能有所帮助，而不是多次复制相同的语句。

public void incrementA(View view) {
    pointsTeamA++;
    if (pointsTeamA == 1) displayA(15);
    if (pointsTeamA == 2) displayA(30);
    if (pointsTeamA == 3) displayA(40);

    if (pointsTeamA == 4) {
        displayGamesA(gameTeamA = gameTeamA + 1);
        displayA(pointsTeamA = 0);
    }
    if (gameTeamA == 6) {
        displaySet1A(gameTeamA);
        displayGamesA(gameTeamA = 0);
        displaySet2A(gameTeamA);
        displayGamesA(gameTeamA = 0);
    }

}

话虽如此，在你向我们提供你所使用的方法之前，你所提到的问题并不完全清楚，所以我们可以看到它们应该做什么。据我所知，每当得分达到6，你就会更新Set 1和Set 2的值;我相信你应该有一个整数变量来跟踪游戏的设置，以及一个if语句内部增量，它根据这个变量更新一组的值。

编辑：以下是如何完成

首先，在类本身中创建一个静态字段。

public static int set = 1;

在任何方法之外，在你的课堂声明之后加上它。

public void incrementA(View view) {
    pointsTeamA++;
    if (pointsTeamA == 1) displayA(15);
    if (pointsTeamA == 2) displayA(30);
    if (pointsTeamA == 3) displayA(40);

    if (pointsTeamA == 4) {
        displayGamesA(gameTeamA = gameTeamA + 1);
        displayA(pointsTeamA = 0);
    }
    if (gameTeamA == 6) {
        if (set == 1) {
            displaySet1A(gameTeamA);
            displayGamesA(gameTeamA = 0);
            set++; // Adds to the set variable, making it 2
        } else if (set == 2) {
            displaySet2A(gameTeamA);
            displayGamesA(gameTeamA = 0);
        }
    }

}

编辑2：处理结果，优势，当分数超过3时获胜。替换先前的if-statement for pointsTeamA == 4

if (pointsTeamA >= 4) {
    if (pointsTeamA - pointsTeamB >= 2) {   // if team A wins

        displayGamesA(gameTeamA = gameTeamA + 1);
        displayA(pointsTeamA = 0);
        displayB(pointsTeamB = 0);
        displayDeuceA(null);
        displayDeuceB(null);
   } else if (pointsTeamA - pointsTeamB == 1) { // score up by one

    // code for displaying "Advantage"  
   } else { // scores are tied
    // code for displaying "Deuce"
   }
}

这个针对网球记分板的Java代码有什么问题

1 个答案: