我正在为城市中的交通创建测试数据库。 我的目标是在任何一站点之间找到路径。 我创建了这张图:
create (Stop_13_1:Tram {Id: 131}),
(Stop_13_2:Tram {Id: 132}),
(Stop_26_1:Tram {Id: 261}),
(Stop_26_2:Tram {Id: 262}),
(Stop_26_3_13_3:Tram {Id: 263133}),
(Stop_26_4_13_4:Tram {Id: 264134}),
(Stop_26_5_13_5:Tram {Id: 265135}),
(Stop_26_6_13_6:Tram {Id: 266136}),
(Stop_26_7_13_7:Tram {Id: 267137}),
(Stop_26_8:Tram {Id: 268}),
(Stop_7_1:Trollebus {Id: 71}),
(Stop_7_2:Trollebus {Id: 72}),
(Stop_7_3:Trollebus {Id: 73}),
(Stop_7_4:Trollebus {Id: 74}),
(Stop_7_5:Trollebus {Id: 75});
当我尝试找到简短的方法时:
match p=shortestPath((a)-[:TO*]-(c))
where a.Id=131 and c.Id=268
return p, length(p) limit 1
或者这个查询:
MATCH (p1:Tram {id: 131}), (p2:Tram {id: 263133}),
path = shortestpath((p1)-[:NEXT*]-(p2))
RETURN path
它没有显示任何路线。 你能帮我编辑查询吗?
P.S。我忘了添加关系:
MATCH (Stop_13_1 {Id: 131}),
(Stop_13_2 {Id: 132}),
(Stop_26_1 {Id: 261}),
(Stop_26_2 {Id: 262}),
(Stop_26_3_13_3 {Id: 263133}),
(Stop_26_4_13_4 {Id: 264134}),
(Stop_26_5_13_5 {Id: 265135}),
(Stop_26_6_13_6 {Id: 266136}),
(Stop_26_7_13_7 {Id: 267137}),
(Stop_26_8 {Id: 268}),
(Stop_7_1 {Id: 71}),
(Stop_7_2 {Id: 72}),
(Stop_7_3 {Id: 73}),
(Stop_7_4 {Id: 74}),
(Stop_7_5 {Id: 75})
MERGE (Stop_13_1)- [:NEXT{distance:4.7,route:13,transport:'tram',direct:'down'}]->(Stop_13_2)
MERGE (Stop_13_2)-[:NEXT{distance:4.7,route:13,transport:'tram',direct:'up'}]->(Stop_13_1)
MERGE (Stop_13_2)-[:NEXT{distance:3.7,route:13,transport:'tram',direct:'down'}]->(Stop_26_3_13_3)
MERGE (Stop_26_3_13_3)-[:NEXT{distance:3.7,route:13,transport:'tram',direct:'up'}]->(Stop_13_2)
MERGE (Stop_26_1)-[:NEXT{distance:5.8,route:26,transport:'tram',direct:'down'}]->(Stop_26_2)
MERGE (Stop_26_2)-[:NEXT{distance:5.8,route:26,transport:'tram',direct:'up'}]->(Stop_26_1)
MERGE (Stop_26_2)-[:NEXT{distance:2.5,route:26,transport:'tram',direct:'down'}]->(Stop_26_3_13_3)
MERGE (Stop_26_3_13_3)-[:NEXT{distance:2.5,route:26,transport:'tram',direct:'up'}]->(Stop_26_2)
MERGE (Stop_26_3_13_3)-[:NEXT{distance:3.1,route:26,route:13,transport:'tram',direct:'down'}]->(Stop_26_4_13_4)
MERGE (Stop_26_4_13_4)-[:NEXT{distance:3.1,route:26,route:13,transport:'tram',direct:'up'}]->(Stop_26_3_13_3)
MERGE (Stop_26_4_13_4)-[:NEXT{distance:5.8,route:26,route:13,transport:'tram',direct:'down'}]->(Stop_26_5_13_5)
MERGE (Stop_26_5_13_5)-[:NEXT{distance:5.8,route:26,route:13,transport:'tram',direct:'up'}]->(Stop_26_4_13_4)
MERGE (Stop_26_5_13_5)-[:NEXT{distance:10.8,route:26,route:13,transport:'tram',direct:'down'}]->(Stop_26_6_13_6)
MERGE (Stop_26_6_13_6)-[:NEXT{distance:10.8,route:26,route:13,transport:'tram',direct:'up'}]->(Stop_26_5_13_5)
MERGE (Stop_26_6_13_6)-[:NEXT{distance:2.5,route:26,route:13,transport:'tram',direct:'down'}]->(Stop_26_7_13_7)
MERGE (Stop_26_7_13_7)-[:NEXT{distance:2.5,route:26,route:13,transport:'tram',direct:'up'}]->(Stop_26_6_13_6)
MERGE (Stop_26_5_13_5)-[:NEXT{distance:0.6,transport:'walking',direct:'down'}]->(Stop_7_2)
MERGE (Stop_7_2)-[:NEXT{distance:0.6,transport:'walking',direct:'up'}]->(Stop_26_5_13_5)
MERGE (Stop_26_8)-[:NEXT{distance:1,route:26,transport:'tram',direct:'down'}]->(Stop_26_7_13_7)
MERGE (Stop_26_7_13_7)-[:NEXT{distance:1,route:26,transport:'tram',direct:'up'}]->(Stop_26_8)
MERGE (Stop_7_1)-[:NEXT{distance:2.2,route:7,transport:'trolleybus',direct:'down'}]->(Stop_7_2)
MERGE (Stop_7_2)-[:NEXT{distance:2.2,route:7,transport:'trolleybus',direct:'up'}]->(Stop_7_1)
MERGE (Stop_7_2)-[:NEXT{distance:1.6,route:7,transport:'trolleybus',direct:'up'}]->(Stop_7_3)
MERGE (Stop_7_3)-[:NEXT{distance:2.5,route:7,transport:'trolleybus',direct:'up'}]->(Stop_7_4)
MERGE (Stop_7_4)-[:NEXT{distance:3.1,route:7,transport:'trolleybus',direct:'down'}]->(Stop_7_5)
MERGE (Stop_7_5)-[:NEXT{distance:4.4,route:7,transport:'trolleybus',direct:'down'}]->(Stop_7_2)
答案 0 :(得分:2)
您尝试匹配具有TO
关系的最短路径,但是您的图表显示关系的类型为NEXT
。
我在这里复制了您的图表http://console.neo4j.org/r/boin78
通过指定正确的关系类型,以下查询正常工作:
match p=shortestPath((a)-[:NEXT*]-(c))
where a.Id=131 and c.Id=268
return p, length(p)
limit 1
对于第二个查询,您使用id
作为属性,而您的节点具有Id
属性名称,以下是有效的:
MATCH (p1:Tram {Id: 131}), (p2:Tram {Id: 263133}),
path = shortestpath((p1)-[:NEXT*]-(p2))
RETURN path