我想显示来自我的数据库的图像，该图像存储图像位置的路径。下面的代码只给出了输出中的图像路径。为了使图像显示而不是图像路径，我需要做出哪些更改？
GetBusinessCategoryList: function () {
debugger;
var data = JSON2.stringify({
});
$.ajax(
{
contentType: "application/json; charset=utf-8",
type: 'POST',
url: 'http://localhost:44719/Modules/BusinessCategoryView/Service/BusinessCategoryWebService.asmx/GetAllBusinessCategory',
dataType: 'json',
data: data,
success: function (result) {
alert("ok");
var returnedData = result;
BusinessManagement.BindBusinessCategoryList(returnedData);
},
error: function (error) {
alert("error");
}
});
},
BindBusinessCategoryList: function (data) {
debugger;
var cLst = data.d;
if (cLst.length > 0) {
headElements += '<table id="customerTable" cellspacing="0" cellpadding="0" >';
headElements += '<thead class="sfHeadingone">';
headElements += '<tr><th align="left">Category Image</th>';
;
headElements += '</thead>';
$('#tblGrid').html(headElements);
var i = 0;
if (i === 0) {
bodyElements += '<tbody>';
}
$.each(cLst, function (index, value) {
bodyElements += "<td>" + value.CategoryImage + "</td>";
}
});