我有一个范围,我想查看它是否有任何形状。
我在网上找到了一个脚本(http://www.mrexcel.com/forum/excel-questions/317711-visual-basic-applications-identify-top-left-cell-selected-range.html),但它对Excel 2003没有用。我到目前为止的代码都是根据找到的脚本改编的:
Public Function removeOLEtypesOfType() As Boolean
On Error Resume Next
Dim objTopLeft As Range, objBotRight As Range _
, objRange As Range, objShape As Shape
Set objRange = Sheet1.Range(COLUMN_HEADINGS)
objRange.Select
With Selection
Dim intFirstCol As Integer, intFirstRow As Integer _
, intLastCol As Integer, intLastRow As Integer
intFirstCol = .Column
intFirstRow = .Row
Set objTopLeft = .Cells(intFirstRow, intFirstCol) '.Address(0, 0)
intLastCol = .Columns.Count + .Column - 1
intLastRow = .Rows.Count + .Row - 1
Set objBotRight = .Cells(intLastRow, intLastCol) '.Address(0, 0)
If objTopLeft Is Nothing Or objBotRight Is Nothing Then
MsgBox "Cannot get topleft or bottom right of range!", vbExclamation
removeOLEtypesOfType = False
Exit Function
End If
For Each objShape In ActiveSheet.Shapes
Dim objTLis As Range
Set objTLis = Intersect(objTopLeft, objShape.TopLeftCell)
If Not objTLis Is Nothing Then
Dim objBRis As Range
Set objBRis = Intersect(objBotRight, objShape.BottomRightCell)
If Not objBRis Is Nothing Then
objShape.Delete
End If
End If
Next
End With
Sheet1.Cells(1, 1).Select
removeOLEtypesOfType = True
End Function
objTopLeft和objBotRight都是Nothing,COLUMN_HEADINGS包含范围的名称。
我在调试器中检查了intFirstCol,intFirstRow,intLastCol和intLastRow,它们是正确的。
编辑...使用.Address注释掉两个topleft和botright范围都返回但是在.Address中,两者都是Nothing。返回的范围似乎不是正确的位置。
例如,对于提供的范围:
intFirstCol = 3
intFirstRow = 11
intLastCol = 3
intLastRow = 186
以上是正确的:
objTopLeft.Column = 5
objTopLeft.Row = 21
objBotRight.Column = 5
objBotRight.Row = 196
上面的不正确,列是+2,行是+10,为什么?
答案 0 :(得分:1)
这似乎是左上角和右下角的一种复杂方式,如果您的选择包含非连续单元格,您的代码将无法正常工作。以下代码可能更合适:
With Selection
Set objTopLeft = .Cells(1)
Set objBottomRight = .Cells(.Cells.Count)
End With
答案 1 :(得分:0)
修正:
Public Function removeOLEtypesOfType() As Boolean
On Error Resume Next
Dim objTopLeft As Range, objBotRight As Range _
, objRange As Range, objShape As Shape
Set objRange = Sheet1.Range(COLUMN_HEADINGS)
objRange.Select
With Selection
Set objTopLeft = .Cells(1)
Set objBotRight = .Cells(.Cells.Count)
If objTopLeft Is Nothing Or objBotRight Is Nothing Then
MsgBox "Cannot get topleft or bottom right of range!", vbExclamation
removeOLEtypesOfType = False
Exit Function
End If
For Each objShape In ActiveSheet.Shapes
Dim blnTLcol As Boolean, blnTLrow As Boolean _
, blnBRcol As Boolean, blnBRrow As Boolean
blnTLcol = (objShape.TopLeftCell.Column >= objTopLeft.Column)
blnTLrow = (objShape.TopLeftCell.Row >= objTopLeft.Row)
blnBRcol = (objShape.BottomRightCell.Column <= objBotRight.Column)
blnBRrow = (objShape.BottomRightCell.Row <= objBotRight.Row)
If blnTLcol = True And blnTLrow = True _
And blnBRcol = True And blnBRrow = True Then
objShape.Delete
End If
Next
End With
Sheet1.Cells(1, 1).Select
removeOLEtypesOfType = True
End Function
谢谢@Ambie我简化了例行程序,无法给出答案,因为这不是问题,但有助于清理代码。
答案 2 :(得分:0)
最简单的方法是从Shape.TopLeftCell创建一个范围到它的Shape.BottomRightCell,然后测试两个范围是否相交。
Set rShageRange = Range(objShape.TopLeftCell, objShape.BottomRightCell)
Sub FindShapesInRange()
Dim objShape As Shape
Dim rSearch As Range, rShageRange As Range
Set rSearch = Range(COLUMN_HEADINGS)
For Each sh In ActiveSheet.Shapes
Set rShageRange = Range(objShape.TopLeftCell, objShape.BottomRightCell)
If Not Intersect(sh.TopLeftCell, rSearch) Is Nothing Then
Debug.Print "Shape Name: " & objShape.Name & " Shape Range: " & rShageRange.Address
End If
Next
End Sub