用C ++将数字转换为英文（1-99）

Question

尝试将数字从1-99转换成英语，但老实说，我不知道我错过了什么。每当我输入20这样的数字时，它就不会像它应该那样输出Twenty。任何帮助，将不胜感激！ ：）

    #include <iostream>
#include <string>
#include <cstdlib>

using namespace std;


int main()
{
    cout << "In this program we will convert integers to English" << endl;

    int Number, leftDigit, rightDigit, yes;
    yes = 1;

    string ones[] = {" Zero"
                     " One "
                     " Two  "
                     " Three "
                     " Four  "
                     " Five  "
                     " Six   "
                     " Seven "
                     " Eight "
                     " Nine  "
                     " Ten   "
                     " Eleven "
                     " Twelve  "
                     " Thirteen"
                     " Fourteen "
                     " Fifteen  "
                     " Sixteen  "
                     " Seventeen "
                     " Eighteen "
                     " Nineteen " };

    string tens[] = {" Twenty "
                     " Thirty "
                     " Fourty  "
                     " Fifty   "
                     " Sixty   "
                     " Seventy "
                     " Eighty  "
                     " Ninety  "};
do{
    cout << "Enter any integer value:  " << endl;
    cin >> Number;

    if ( Number <= 0 || Number >= 100 )
    {
        cout << "The number is not between 1 and 99" << endl;
    }
    else ( Number >= 1 && Number <= 19 )
    {
        cout << "The number you have entered is: " << ones[Number] << endl;
    }
    else ( Number >= 20 && Number <= 99)
    {
        leftDigit = Number / 10;
        rightDigit = Number % 10;

        cout << "The number you have entered is: " << tens[leftDigit - 2 ] << " " << ones[rightDigit] << endl;
    }
  } while (yes == 1);

    return 0;
}

Answer 1

您的代码中有两个问题：

首先，您需要在string ones[]和string tens[]之间的参数之间添加逗号：

string tens[] = { " Twenty ",
        " Thirty ",
        " Fourty  ",
        " Fifty   ",
        " Sixty   ",
        " Seventy ",
        " Eighty  ",
        " Ninety  " };

第二次，您需要在每个if中添加else，如下所示：

// ..
else if (Number >= 1 && Number <= 19)
                {
                    cout << "The number you have entered is: " << ones[Number] << endl;
                }
// ..

修复这两个问题后，代码

结果：