欢迎 注意:未定义的变量:第6行的C:\ xampp \ xamp \ my文件夹\ htdocs \ login-form \ login \ login_success.php中的myusername 没有*
当我尝试使用此代码时,这是我项目的错误。我想添加欢迎(用户名)。我认为我的login_success中出现了错误,但我无法弄明白。请帮帮我
-------------- checklogin.php ---------------------------
<?php
ob_start();
$host="localhost";
$username="root";
$password="root";
$db_name="test";
$tbl_name="members";
mysql_connect($host,$username,$password)or die("cannot connect");
mysql_select_db($db_name)or die("cannot select DB");
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];
$myusername=stripslashes($myusername);
$mypassword=stripslashes($mypassword);
$myusername=mysql_real_escape_string($myusername);
$mypassword=mysql_real_escape_string($mypassword);
$sql="SELECT * FROM $tbl_name WHERE Username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
if($count==1){
$_SESSION['myusername'] = $myusername;
$_SESSION['mypassword'] = $mypassword;
header("location:login_success.php");
}
else{
echo "Wrong Username or Password";
}
ob_end_flush();
?>
------------------ login_success.php -------------------------- -
<li><a href="#">Welcome
<?php
session_start();
$_SESSION['myusername'] = $myusername;
if(isset($_SESSION['myusername']))
{
echo "ok";
}
else
{
echo "no";
}
?>
答案 0 :(得分:1)
您需要在login_success.php
中查看此行$_SESSION['myusername'] = $myusername;
此处,您已在登录后的previuos页面中存储了$ _SESSION ['myusername']。此行表示您尝试使用$ myusername覆盖$ _SESSION ['myusername']。
但是,我们的目标是阅读$ _SESSION ['myusername']并将其存储在$ myusername中。 所以,简单地交换双方:
$myusername = $_SESSION['myusername']
试试这个:
session_start();
$myusername = $_SESSION['myusername'];
if (isset($_SESSION['myusername'])) {
echo "User".$username." is logged in";
} else {
echo "No user is logged in.";
}
-checklogin.php -
$sql = "SELECT * FROM $tbl_name WHERE Username='$myusername' and password='$mypassword'";
$result = mysql_query($sql) or die(mysql_error()); // Check if you get any SQL syntax error
$count = mysql_num_rows($result);
var_dump($count); // Check the value of $count
exit;
答案 1 :(得分:0)
$_SESSION['myusername'] = $myusername;
您正尝试将$myusername
的值分配给$_SESSION['myusername']
。
但你必须做相反的事情。
$myusername = $_SESSION['myusername'];
答案 2 :(得分:0)
session_start();
$myusername = $_SESSION['myusername'];
if (isset($_SESSION['myusername'])) {
echo "User".$username." is logged in";
}
如果$_SESSION['myusername']
为空/空,如果您不想显示任何内容,请省略else部分。