Question

from tkinter import *

player1 = []
player2 = []

class MakeSq:

    def __init__(self, master):
        self.master = master
        self.sqs()
        self.again()

    def sqs(self):
        self.square_frame = (self.master)
        self.square_frame.grid()
        self.quan = 17 # make this game universal, you can add more squares
        for s in range(1, self.quan * self.quan + 1, 1):
            self.b = s
            self.b = Button(self.master, width=3, command=lambda x=s: self.mark(x), font=('times', 16))
            self.b['command'] = lambda x=s, which=self.b: self.mark(x, which)
            self.place_it(s) # place square on the right place
            self.b.grid(row=self.r, column=self.c)

    def place_it(self, s):
        self.r = 0
        while s > self.quan:
            s -= self.quan
            self.r += 1
        self.c = s % (self.quan + 1)

    def mark(self,x , which):
        if len(player1) == len(player2):
            player1.append(x)
        else:
            player2.append(x)
        if len(player1) == len(player2):
            p = 'O'
            p_c = 'dark blue'
        else:
            p = 'X'
            p_c = 'orange'
        which.config(text=p, fg=p_c, command='')
        self.check_win(player1)
        self.check_win(player2)


    def check_win(self, player):
        for p in player: # iba p + 4 moze byt delitelne 17, kluc k vyrieseniu problemu s riadkami
            if p + 1 in player and p + 2 in player and p + 3 in player and p + 4 in player:
                print('win')

            elif p + 17 in player and p + 34 in player and p + 51 in player and p + 68 in player:
                print('win')

            elif p + 18 in player and p + 36 in player and p + 54 in player and p + 72 in player:
                print('win')

            elif p + 16 in player and p + 32 in player and p + 48 in player and p + 64 in player:
                print('win')


    def again(self):
        self.again_bt = Button(self.master, text='New game', command=self.restart)
        self.again_bt.grid(column=200)

    def restart(self):
        self.sqs()
        player1.clear()
        player2.clear()

    def show_result(self):
        pass


root = Tk()
plan = MakeSq(root)
root.mainloop()

此代码创建289个按钮。我如何具体说明每个按钮？例如，如果我单击按钮编号50，则此按钮将激活功能self.mark()，但如何在不单击按钮的情况下激活特定按钮的功能self.mark()。

修改我编辑了我的代码，你现在可以运行它。我想创造Tic-Tac-Toe游戏。此代码应为两个玩家创建游戏。如果单击按钮，按钮文本将更改。功能self.mark()的目的是更改按钮的文本并检查是否有人获胜。它有效，但是我想要添加机器人/计算机来对付我。所以在我移动（点击按钮）之后，机器人将会采取行动。将会有找到最佳动作的功能，并执行此操作（它应该更改特定按钮的文本而不单击此按钮）。 如何在不点击此按钮的情况下更改特定按钮的文字？

Answer 1

您正在使用.grid（）方法来放置/分组您的小部件（主要是按钮），以便您可以使用它来识别按钮所在的行/列。

    def mark(self,x , which):
        ...

        # Lets say human is using 'X' marks (player1)
        # So the bot is left with 'O'.
        if p == 'X': self.BotMakeMove(which) # Human made a move so it's Bots turn

    def BotMakeMove(self, button):
        row     = int(button.grid_info()['row'])
        column  = int(button.grid_info()['column'])

        print ("Human pressed button at index: {} {}".format(row, column))

        # Do some calculation
        # 
        # 


        # You're done and lets say you wont to press the button right of humans
        row     = row           # ...
        column  = column + 1

        self.press(row, column)


    def press(self, row, column):
        for children in self.master.children.values():                                                                 
            if children.grid_info()['row'] == str(row) and children.grid_info()['column'] == str(column) and children['command']:
                player2.append(0)           # You should pass that 'x' value here.
                children.config(text='O', fg='dark blue', command='')
                return True

        print ("Button at index {} {} doesnt exist or is being used.".format(row, column))

python，tkinter特定按钮

1 个答案: