Question

当我尝试在iPhone上运行以下代码时，出现以下错误

rrr.swift:356:72: Ambiguous use of 'subscript'

奇怪的是，只有当我想在手机上运行应用程序时，才能在模拟器上运行，但它运行正常。

有3行会导致错误。我在下面的大写字母中注明了它们。我尝试访问JSON数组中的数组中的属性，我怀疑我这样做是错误的，但不知道如何解决它。

如何在没有下标错误的情况下检索这些属性？

 self.restApi.getSchoolDetails(schoolId) {responseObject, error in
        // use responseObject and error here

         self.schoolDetailsCollection = NSDictionary(dictionary: responseObject! as! [String : AnyObject])
         print(self.schoolDetailsCollection)

        if let response = responseObject as? NSDictionary {
           //parse the response object
            self.schoolDetailsList = (response as? NSDictionary)!

            //assigning all values to shareData class
            self.shareData.sco_id = response["result"]!["sco_id"] as!NSInteger
            self.shareData.address = response["result"]!["address"] as!String
            self.shareData.name = response["result"]!["name"] as! String
            print("school name")
            print(self.shareData.name)
            self.shareData.intro = response["result"]!["intro"] as! String
           self.shareData.sell_point = response["result"]!["sell_point"] as! String
            self.shareData.city = response["result"]!["city"] as! String
            self.shareData.cou_id = response["result"]!["cou_id"] as! String

            //get images from the nested array in the json array
            /THESE THREE LINES CAUSE THE ERROR SUBSRCIPT
             self.shareData.image1 = response["result"]!["images"][0]! as! String
            self.shareData.image2 = response["result"]!["images"]![1] as! String
            self.shareData.image3 = response["result"]!["images"]![2] as! String

            print(self.shareData.image1)
            print(self.shareData.image2)
            print(self.shareData.image3)



            //open next controller after all info has been set correctly
            //info is being passed by Singleton class Sharedata
            if let COBezierDemoViewController = self.storyboard!.instantiateViewControllerWithIdentifier("COBezierDemoViewController") as? COBezierDemoViewController {
                self.presentViewController(COBezierDemoViewController, animated: true, completion: nil)
            }

        }

    }

}

JSON文件：

{
result =     {
    address = "223 Vincent St, West Perth WA 6005, Australia";
    city = Perth;
    "cou_id" = AU;
    "cur_id" = "";
    environment = R;
    financed = "<null>";
    images =         (
        "Phoenix_Academy_1.jpeg",
        "Phoenix_Academy_3.jpeg",
        "Phoenix_Academy_2.jpeg"
    );
    intro = "Our language school in Perth has a modern campus and a spacious garden. The language school is located 10 minutes north from the city center. You can reach the city center and the famous bea

Answer 1

正如您在此行中提示错误：

 self.shareData.image1 = response["result"]!["images"][0]! as! String

错误：

错误是您在AnyObject中实现的[0]下标。

response["result"]!["images"] // this is returning Optional<AnyObject> which do not have subscript option.

正确的方法应该是：

Downcast AnyObject as? [String] //这将返回nil或Array<String?>，其中String是图片名称。

如果没有向下转换，您将收到错误：对下标的模糊使用。

let images = response["result"]? ["images"] as? [String] images?.flatMap({ $0 }).forEach { print($0) // Phoenix_Academy_1.jpeg, Phoenix_Academy_3.jpeg, Phoenix_Academy_2.jpeg }

仅在实际设备上模糊使用下标错误

1 个答案: