MongoDB - 我如何将此group（）查询转换为map / reduce

Question

我有一个集合，每个文档都是这样的

{access_key:'xxxxxxxxx', keyword: "banana", count:12, request_hour:"Thu Sep 30 2010 12:00:00 GMT+0000 (UTC)"}
{access_key:'yyyyyyyyy', keyword: "apple", count:25, request_hour:"Thu Sep 30 2010 12:00:00 GMT+0000 (UTC)", }
.....

实现这一目标：

SELECT keyword, sum(count) FROM keywords_counter WHERE access_key = 'xxxxxxxxx' GROUP BY keyword

我这样做：

db.keywords_counter.group({key     : {keyword:true}, 
                          cond    : {access_key: "xxxxx"}, 
                          reduce  : function(obj, prev){prev.total += obj.count},
                          initial : {total:0}})

如何使用map / reduce实现相同的功能？ [我是一张地图/缩小初学者并尝试围绕这个概念。]

Answer 1

找到解决方案：

map = function(){ emit(this.keyword, {count: this.count}); }

reduce = function(key, values){
             var total = 0;
             for (var i=0; i < values.length, i++) { total += values[i].count; }
             return {count: total};
         }

db.keywords_counter.mapReduce(map, reduce, {query:{access_key: 'xxxxxxxxx'}})