Question

这可能是一个重复的问题，但我已经全面检查过，无法找到iOS9的工作答案。 -stringByAddingPercentEscapesUsingEncoding已被弃用。我需要使用-stringByAddingPercentEncodingWithAllowedCharacters

下面是需要反斜杠转义的字符串，以便API可以验证会话并返回响应。

NSString *base = @"http://domain.com/interface/?end=imember";
NSCharacterSet *set = [NSCharacterSet URLQueryAllowedCharacterSet];
NSString *key = [@"&client_key=KOB3N6KX9JXF2MRPO5U.BRFYM7TYVE\/16KIJVXZA6R7H\/1LD1K\/JYIYG7IZP2HA7NUYOVNT3CJG==&token=SGD7E9B29TQ.8HIITZ37XW3GLK5OGLZNLCDM=" stringByAddingPercentEncodingWithAllowedCharacters:set];

标准的URL字符集不会逃避反斜杠，我已经尝试了所有这些：

URLUserAllowedCharacterSet
URLPasswordAllowedCharacterSet
URLHostAllowedCharacterSet
URLPathAllowedCharacterSet
URLQueryAllowedCharacterSet
URLFragmentAllowedCharacterSet

如果有人可以提供帮助，我对发展很陌生。是否可以创建包含反斜杠的自定义允许集？

编辑：

这就是网址的样子：

http://domain.com/interface/?end=imember&client_key=KOB3N6KX9JXF2MRPO5U.BRFYM7TYVE\/16KIJVXZA6R7H\/1LD1K\/JYIYG7IZP2HA7NUYOVNT3CJG==&token=SGD7E9B29TQ.8HIITZ37XW3GLK5OGLZNLCDM=

Answer 1

你回答的确切解决方法如下。我是从Zaph's answer得到的。这是比其他答案更好的答案。

NSString *unescaped = @"http://domain.com/interface/?end=imember"];
NSString *escapedString = [unescaped stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
NSLog(@"escapedString: %@", escapedString);

URL编码字符集

URLFragmentAllowedCharacterSet  "#%<>[\]^`{|}
URLHostAllowedCharacterSet      "#%/<>?@\^`{|}
URLPasswordAllowedCharacterSet  "#%/:<>?@[\]^`{|}
URLPathAllowedCharacterSet      "#%;<>?[\]^`{|}
URLQueryAllowedCharacterSet     "#%<>[\]^`{|}
URLUserAllowedCharacterSet      "#%/:<>?@[\]^`

NSURL：使用NSCharacterSet

1 个答案: