Question

我想在我的应用程序中包含facebook登录信息。这是我提供的示例代码：

    <?php

require 'facebook.php';

// Create our Application instance (replace this with your appId and secret).
$facebook = new Facebook(array(
  'appId'  => 'my api goes here',
  'secret' => 'my api secret goes here',
  'cookie' => true,
));

// We may or may not have this data based on a $_GET or $_COOKIE based session.
//
// If we get a session here, it means we found a correctly signed session using
// the Application Secret only Facebook and the Application know. We dont know
// if it is still valid until we make an API call using the session. A session
// can become invalid if it has already expired (should not be getting the
// session back in this case) or if the user logged out of Facebook.
$session = $facebook->getSession();

$me = null;
// Session based API call.
if ($session) {
  try {
    $uid = $facebook->getUser();
    $me = $facebook->api('/me');
  } catch (FacebookApiException $e) {
    error_log($e);
  }
}

// login or logout url will be needed depending on current user state.
if ($me) {
  $logoutUrl = $facebook->getLogoutUrl();
} else {
  $loginUrl = $facebook->getLoginUrl();
}
?>
<!doctype html>
<html xmlns:fb="http://www.facebook.com/2008/fbml">
  <head>
    <title>php-sdk</title>
    <style>
      body {
        font-family: 'Lucida Grande', Verdana, Arial, sans-serif;
      }
      h1 a {
        text-decoration: none;
        color: #3b5998;
      }
      h1 a:hover {
        text-decoration: underline;
      }
    </style>
  </head>
  <body>
    <!--
      We use the JS SDK to provide a richer user experience. For more info,
      look here: http://github.com/facebook/connect-js
    -->
    <div id="fb-root"></div>
    <script>
      window.fbAsyncInit = function() {
        FB.init({
          appId   : '<?php echo $facebook->getAppId(); ?>',
          session : <?php echo json_encode($session); ?>, // don't refetch the session when PHP already has it
          status  : true, // check login status
          cookie  : true, // enable cookies to allow the server to access the session
          xfbml   : true // parse XFBML
        });

        // whenever the user logs in, we refresh the page
        FB.Event.subscribe('auth.login', function() {
          window.location.reload();
        });
      };

      (function() {
        var e = document.createElement('script');
        e.src = document.location.protocol + '//connect.facebook.net/en_US/all.js';
        e.async = true;
        document.getElementById('fb-root').appendChild(e);
      }());
    </script>


    <h1><a href="example.php">php-sdk</a></h1>

    <?php if ($me): ?>
    <a href="<?php echo $logoutUrl; ?>">
      <img src="http://static.ak.fbcdn.net/rsrc.php/z2Y31/hash/cxrz4k7j.gif">
    </a>
    <?php else: ?>
    <div>
      Using JavaScript &amp; XFBML: <fb:login-button></fb:login-button>
    </div>
    <div>
      Without using JavaScript &amp; XFBML:
      <a href="<?php echo $loginUrl; ?>">
        <img src="http://static.ak.fbcdn.net/rsrc.php/zB6N8/hash/4li2k73z.gif">
      </a>
    </div>
    <?php endif ?>

    <h3>Session</h3>
    <?php if ($me): ?>
    <pre><?php print_r($session); ?></pre>

    <h3>You</h3>
    <img src="https://graph.facebook.com/<?php echo $uid; ?>/picture">
    <?php echo $me['name']; ?>
    <?php echo $me['education'][0]['school']['name']; ?>

    <h3>Your User Object</h3>
    <pre><?php print_r($me); ?></pre>
    <?php else: ?>
    <strong><em>You are not Connected.</em></strong>
    <?php endif ?>

    <h3>Naitik</h3>
    <img src="https://graph.facebook.com/naitik/picture">
    <?php echo $naitik['name']; ?>
  </body>
</html>

现在 - 这很好用，但是当我试图在我的代码点火器视图文件中包含它时，由于错误，它不允许我登录。在代码中，它表示“我的api在这里”和“我的api秘密在这里”，我显然是在插入我的应用数据。你们有没有遇到类似的问题？当我点击登录时，我收到此错误：MY APP出错。请稍后再试。

任何人都可以帮我这个吗？

Answer 1

你有没有为Facebook试过这两个CodeIgniter库？

更新：遗憾的是，这些链接不再有效。

Answer 2

我的合作伙伴刚刚建立了一个图书馆并且深深地帮助解决了这个问题： http://hitsend.ca/2010/10/facebook-connect-user-authentication-using-the-new-graph-api-in-codeigniter/

让我们知道您的想法。我们需要它用于我们的用途，并认为这是一个常见的问题。它使用新的图形api，而不是旧图形。这解决了很多问题。

让我们知道您的想法。

不能在我的codeigniter项目中包含facebook

2 个答案: