Question

DECLARE @Table1 TABLE 
        (ID int, STATUS varchar(1))
    ;

    INSERT INTO @Table1
        (ID, STATUS)
    VALUES
        (1,  'A'),
        (1,  'A'),
        (1,  'A'),
        (1,  'B'),
        (1,  'A'),
        (2,  'C'),
        (2,  'C')
    ;

脚本：

Select *,ROW_NUMBER()OVER(PARTITION BY STATUS ORDER BY (SELECT NULL))RN from @Table1

获取结果集

ID  STATUS  RN
1   A       1
1   A       2
1   A       3
1   A       4
1   B       1
2   C       1
2   C       2

需要输出

ID  STATUS  RN
1   A       1
1   A       2
1   A       3
1   B       1
1   A       1
2   C       1
2   C       2

Answer 1

试试这个

DECLARE @Table1 TABLE 
        (ID int, STATUS varchar(1));

INSERT INTO @Table1
    (ID, STATUS)
VALUES
    (1,  'A'),
    (1,  'A'),
    (1,  'A'),
    (1,  'B'),
    (1,  'A'),
    (2,  'C'),
    (2,  'C');

;WITH Tmp
AS 
(    
    SELECT *, ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) AS RowNumber FROM @Table1
)


SELECT
    A.ID ,
    A.STATUS ,      
    ROW_NUMBER() OVER (PARTITION BY A.STATUS, (A.RowNumber - A.RN)  ORDER BY (SELECT NULL)) AS RN
FROM
(
    Select *, ROW_NUMBER() OVER(PARTITION BY STATUS ORDER BY RowNumber) AS RN from tmp

) A
ORDER BY
    A.RowNumber

输出：

ID          STATUS RN
----------- ------ ------
1           A      1
1           A      2
1           A      3
1           B      1
1           A      1
2           C      1
2           C      2

Answer 2

首先，在您发布的插入语句中。 4如何与1,2和3不同，如果它基于不同的列，则在＃34; row_number＆＃34;中包含该列。在子句中的分区。因为否则它会认为＆＃39; A＆＃39;在4和＆＃39; A＆＃39; 1,2,3是相同的，因此将它们组合在一起。

INSERT INTO @Table1
  (ID, STATUS)
VALUES
  (1,  'A'),   <--  1
  (1,  'A'),   <--  2
  (1,  'A'),   <--  3
  (1,  'B'),
  (1,  'A'),   <--  4
  (2,  'C'),
  (2,  'C')
;

如何在VARCHAR列上进行分区

2 个答案: