Question

获取无效的块标记消息Invalid block tag on line 2: 'out'. Did you forget to register or load this tag?但不知道原因。这是我的设置：

graphs.html

{% out %}

views.py

out = 'something to say'
template = loader.get_template('viz_proj/graphs.html')
context = {
    'out' : out
} 
return HttpResponse(template.render(context, request))

settings.py

INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'viz_proj'
]

项目heirarchy

viz_proj
|
viz_proj----------------------------------------templates
    |                                              |
    settings.py--views.py--urls.py               graphs.html

Answer 1

我想你想尝试{{out}}而不是{％out％}。

Answer 2

解决方案是{{out}}而不是{% out %}。这是因为out是一个变量。

参考：https://docs.djangoproject.com/en/1.11/topics/templates/#the-django-template-language

无效的块标记。您是否忘记注册或加载此标记？

2 个答案: