Question

我有一个Animal类，它由两个类扩展：

@XmlRootElement
@Entity
@Table(name="class_animal")
@Inheritance(strategy = InheritanceType.JOINED)
@DiscriminatorColumn(name="type", discriminatorType=DiscriminatorType.STRING,length=31)
@DiscriminatorValue("animal")
@Cacheable
@Cache(coordinationType=CacheCoordinationType.INVALIDATE_CHANGED_OBJECTS, alwaysRefresh=true, expiry=300)
public class Animal {
    @Id @Column(name="uuid")        private String id;
    @Column(name="owner")           private String owner;
    @Column(name="name")            private String name;
    @Column(name="type")            private String type;
}

Cat类扩展Animal

@Entity
@Table(name="class_animal_cat")
@Cacheable
@Cache(coordinationType=CacheCoordinationType.INVALIDATE_CHANGED_OBJECTS, alwaysRefresh=true, expiry=300)
@DiscriminatorValue("cat")
public class Cat extends Animal {
    // ...
}

Mouse类，扩展Animal

@Entity
@Table(name="class_animal_mouse")
@Cacheable
@Cache(coordinationType=CacheCoordinationType.INVALIDATE_CHANGED_OBJECTS, alwaysRefresh=true, expiry=300)
@DiscriminatorValue("mouse")
public class Mouse extends Animal {
    // ...
}

我使用以下（简化）语法接收所有动物：

ExpressionBuilder builder = new ExpressionBuilder(Animal.class);
ReadAllQuery databaseQuery = new ReadAllQuery(type, builder);
Expression exp = builder.getField("owner").equal("Thomas");
databaseQuery.setSelectionCriteria(exp);
Query query = ((JpaEntityManager)em.getDelegate()).createQuery(databaseQuery);
List<Animal> resultsList = query.getResultList();

只要数据库中没有任何项目，一切都很好，我得到一个空列表。

如果我添加“Cat”类型的项目，我会收到以下错误：

Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.1.v20130918-f2b9fc5): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: com.microsoft.sqlserver.jdbc.SQLServerException: Invalid column name 'owner'.
Error Code: 207
Call: SELECT t0.uuid, t0.type, t0.name, t0.owner, t1.uuid FROM class_animal t0, class_animal_cat t1 WHERE ((t1.owner = ?) AND ((t1.uuid = t0.uuid) AND (t0.type = ?)))
    bind => [2 parameters bound]
Query: ReadAllQuery(referenceClass=Animal sql="SELECT DISTINCT type FROM class_animal WHERE (owner = ?)")

t1.owner的字段访问权限错误 - t0.owner是正确的。如何配置/分配字段以始终回退到Animal.owner而不是i.E. Cat.owner？

Eclipse Link在InheritanceType.JOINED继承的类中使用错误的字段映射

0 个答案: