如何在PHP中使用select语句在另一个DropDownList中选择另一个值后，自动在dropdownList中选择一个值

Question

参考下面的图片，如果有人能抽出时间帮助我，我会很高兴。我想选择Section Location，例如Sales Floor，它将选择相应的sectionLocationID并将其附加到Dropdown输入框标记的Section Location右侧的小下拉框中。我正在使用查询在下拉框中检索值：SELECT locationName，locationID FROM locationDetails ORDER BY locationName

以下是整个代码      //准备声明                 if（$ stmt = $ sqlcon-＆gt; prepare（＆＃34; SELECT locationName，locationID FROM locationDetails ORDER BY locationName＆＃34;））{

                $stmt->execute();
                //get result
                $result = $stmt->get_result();
            }

            echo  "<select name='clocation' class='input username'>";


            echo '<option placeholder="'.$placeholdergender.'">'.$placeholdergender.'</option>';
            while($row=$result->fetch_row())
            {

                $section=$row['0'];
               // $sectionID=$row['1'];


                echo '<option value="'.$section.'">'.$section.'</option>';

            }
           // echo '<input type="text" value="'.$sectionID.'">';
            echo '</select>';
            echo '<select>';

            echo  "<select name='cID' class='input username'>";

           // echo '<option placeholder="'.$placeholdergender.'">'.$placeholdergender.'</option>';
            while($row=$result->fetch_row())
            {

               // $section=$row['0'];
                 $sectionID=$row['1'];


                echo '<option value="'.$sectionID.'">'.$sectionID.'</option>';

            }
            // echo '<input type="text" value="'.$sectionID.'">';



            echo '</select>';

            echo '<br>';


            ?>