尝试将共享按钮添加到iPad代码时，我一直收到错误消息

Question

我在调用代码时一直收到popovercontroller错误，这是我的代码：

- (IBAction)sharePost:(id)sender {
    NSArray *activityItems;
    NSInteger tid = ((UIControl *) sender).tag;

    if ([catName isEqualToString:@"All"])
    {
        //UIImage *snapshotImage = [self imageFromView:self.view];
        activityItems = @[[self.titleArray objectAtIndex:tid],[self.linkArray objectAtIndex:tid],[self.imageArray objectAtIndex:tid]];
    }
    else
    {
        activityItems = @[[self.titleCatArray objectAtIndex:tid],[self.linkCatArray objectAtIndex:tid],[self.imageCatArray objectAtIndex:tid]];
    }

    UIActivityViewController *activityController =

    [[UIActivityViewController alloc]

     initWithActivityItems:activityItems

     applicationActivities:nil];

    [self presentViewController:activityController         
                       animated:YES completion:nil];        
}

- (void)didReceiveMemoryWarning
{
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}

我想让它在iPad上工作，我已经在线查看了所有内容，但无法弄明白。

Answer 1

在UIActivityViewController的文档中：

  

在iPad上，您必须在弹出窗口中显示视图控制器。在iPhone和iPod touch上，您必须以模态方式呈现它。

尝试：

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
    UIPopoverController *popover = [[UIPopoverController alloc] initWithContentViewController:activityController];
    [popover presentPopoverFromRect:[sender bounds]
                             inView:sender        
           permittedArrowDirections:UIPopoverArrowDirectionAny        
                           animated:YES];
    self.popover = popover;
} else {
    [self presentViewController:activityController
                       animated:YES
                     completion:nil];
}