Question

我试图在JS中按升序排列一些数字，但它似乎无法工作，我得到以下控制台日志：[1,2,3,6,9,1,2,3,4,6， 8,9,12,18,18,24,36,72]

以下是代码：

var firstNum = 18;
var secondNum = 72;
var array = [];
var otherArray = [];

for (i = 0; i <= firstNum; i++) {
    if(firstNum % i === 0) {
        array.push(i);
    }
}

for (j = 0; j <= secondNum; j++) {
    if(secondNum % j ===0) {
        array.push(j);
    }
}

for (k = 0; k < array.length; k++) {
    if(array[k] > array[k+1]) {
        var temp = array[k];
        array[k] = array[k+1];
        array[k+1] = temp;
        }
    }


console.log(array)
console.log(otherArray)

感谢帮助。

Answer 1

您可以像这样修改代码：

for (i = 0; i <= arrayX.length-1; i++)
  {
    if (arrayX[i] > arrayX[i+1])
      {
        temp = arrayX[i+1];
        arrayX[i+1] = arrayX[i];
        arrayX[i] = temp;
        i = i-2;
      }
  }

＆＃13;

var firstNum = 18;
var secondNum = 72;
var array = [];
var otherArray = [];

for (i = 0; i <= firstNum; i++) {
  if (firstNum % i === 0) {
    array.push(i);
  }
}

for (j = 0; j <= secondNum; j++) {
  if (secondNum % j === 0) {
    array.push(j);
  }
}

for (i = 0; i <= array.length - 1; i++) {
  if (array[i] > array[i + 1]) {
    temp = array[i + 1];
    array[i + 1] = array[i];
    array[i] = temp;
    i = i - 2;
  }
}
alert(array)

＆＃13;

希望它可以帮助你：）

Answer 2

Use otherArray also like
for (j = 0; j <= secondNum; j++) {
    if(secondNum % j ==0) {
        otherArray.push(j);

    }
}
then print by using the same logic of temp it will give individual array output in ascending order and if you want to join two array output then use concat/merge and then print

无法在JS中按升序排列数组项

2 个答案: