Question

我正在使用angularjs 1.我有一个非常复杂的json对象，有很多嵌套。我想在json上使用ng-repeat来访问嵌套数组。

 [{
   "information": {
     "name": "simdi jinkins",
     "phone": "08037775692",
     "email": "sim04ful@gmail",
     "whatsapp": "8349493420",
     "residential": "gwarinpa",
     "office": "dansarari plaza"
   },
   "jobs": [{
     "name": "jeans and shirt",
     "measurement": {
       "shoulder": "34",
       "waist": "44",
       "neck": "86",
       "front": "42",
       "length": "33",
       "boost": "80",
       "cap": "30",
       "sleeves": "12",
       "tommy": "30",
       "thigh": "30",
       "chest": "34",
       "back": "40"
     },
     "account": {
       "method": "cheque",
       "amount": "2334",
       "advance": "3945",
       "date": "2016-07-22T09:54:06.395Z"
     },
     "date": {
       "incharge": "2016-07-22T09:54:06.395Z",
       "collection": "2016-07-22T09:54:06.395Z"
     },
     "style": "english",
     "material": "our"
   }, {
     "name": "skirt and blouse",
     "measurement": {
       "shoulder": "35",
       "waist": "45",
       "neck": "85",
       "front": "52",
       "length": "53",
       "boost": "85",
       "cap": "50",
       "sleeves": "52",
       "tommy": "50",
       "thigh": "35",
       "chest": "35",
       "back": "50"
     },
     "account": {
       "method": "cheque",
       "amount": "2334",
       "advance": "5045",
       "date": "2016-07-22T09:54:06.395Z"
     },
     "date": {
       "incharge": "2016-07-22T09:54:06.395Z",
       "collection": "2016-07-22T09:54:06.395Z"
     },
     "style": "native",
     "material": "bought"
   }]
 }, {
   "information": {
     "name": "Paula Odama",
     "phone": "08034698692",
     "email": "paulyd@gmail",
     "whatsapp": "8348733420",
     "residential": "inpa",
     "office": "dansaza"
   },
   "jobs": [{
     "name": "gown",
     "measurement": {
       "shoulder": "74",
       "waist": "44",
       "neck": "76",
       "front": "42",
       "length": "73",
       "boost": "80",
       "cap": "37",
       "sleeves": "72",
       "tommy": "30",
       "thigh": "70",
       "chest": "37",
       "back": "70"
     },
     "account": {
       "method": "cheque",
       "amount": "2334",
       "advance": "3945",
       "date": "2016-07-22T09:54:06.395Z"
     },
     "date": {
       "incharge": "2016-07-22T09:54:06.395Z",
       "collection": "2016-07-22T09:54:06.395Z"
     },
     "style": "english",
     "material": "our"
   }, {
     "name": "robes",
     "measurement": {
       "shoulder": "35",
       "waist": "45",
       "neck": "85",
       "front": "52",
       "length": "53",
       "boost": "85",
       "cap": "50",
       "sleeves": "52",
       "tommy": "50",
       "thigh": "35",
       "chest": "35",
       "back": "50"
     },
     "account": {
       "method": "cheque",
       "amount": "2334",
       "advance": "5045",
       "date": "2016-07-22T09:54:06.395Z"
     },
     "date": {
       "incharge": "2016-07-22T09:54:06.395Z",
       "collection": "2016-07-22T09:54:06.395Z"
     },
     "style": "native",
     "material": "bought"
   }]
 }];

我正在尝试访问我尝试过以下的作业中的name属性

<div ng-repeat="customer in customers" class="card rich-card" z="2">
  <div class="card-hero" style="">
    <h1>{{customer.jobs.name}} <span>{{}}</span> </h1> 
  </div>
  <div class="divider"></div>
  <div class="card-footer">
    <button class="button flat">View</button>
    <button class="button flat color-orange-500">Explore</button>
  </div>
</div>

Answer 1

因为customer.jobs是一个数组，所以必须使用和索引或键访问它。

在您的示例中，执行此操作的方法是使用customer.jobs [0] .name。

生成的HTML会这样：

<div ng-repeat="customer in customers" class="card rich-card" z="2">
    <div class="card-hero" style="">
        <div data-ng-repeat="job in customer.jobs">
            <h1>{{job.name}} <span>{{}}</span> </h1> 
        </div>
    </div>
    <div class="divider"></div>
    <div class="card-footer">
        <button class="button flat">View</button>
        <button class="button flat color-orange-500">Explore</button>
    </div>
</div>

<强>更新

这是一系列客户，每个客户都包含一系列工作。因此，您需要一个双中继器来循环第一个和第二个数组。

更新2

我想你可能想要一张卡片＆＃39;根据客户的每项工作，该代码如下：

<div data-ng-repeat="customer in customers">
    <div ng-repeat="job in customer.jobs" class="card rich-card" z="2">
        <div class="card-hero" style="">
            <h1>{{job.name}} <span>{{}}</span> </h1> 
        </div>
        <div class="divider"></div>
        <div class="card-footer">
            <button class="button flat">View</button>
            <button class="button flat color-orange-500">Explore</button>
        </div>
    </div>
</div>

Answer 2

你没有明确说你的数组被称为客户，所以我假设它是。

您拥有一系列客户，每个客户都有一个或多个工作。如果要为每个客户显示所有作业的名称，则需要使用嵌套的ng-repeats。我不确定你想要重复你的UI的哪一部分，但我只是选择'卡片 - 英雄'div。

<div ng-repeat="customer in customers" class="card rich-card" z="2">
    <h1>{{customer.information.name}}</h1>
  <div ng-repeat="job in customer.jobs" class="card-hero" style="">
    <h2>{{job.name}} <span>{{}}</span> </h2> 
  </div>
  <div class="divider"></div>
  <div class="card-footer">
    <button class="button flat">View</button>
    <button class="button flat color-orange-500">Explore</button>
  </div>
</div>

编辑：添加了h1客户名称，并将作业名称更改为h2，以显示每个客户下的每个作业都显示

以角度js访问嵌套对象中的嵌套数组

2 个答案: