Question

如何填补表格的空白。我有一个示例数据

DECLARE @Table TABLE 
( Rule_ID VARCHAR(10),
  Name    VARCHAR(10),
  Age     INT
)
INSERT INTO @Table(Rule_ID,Name,Age) 
VALUES
('Rule_01','Mohan',29),
('Rule_01','Manasa',25),
('Rule_03','Raju',29),
('Rule_03','Miju',25),
('Rule_05','Ramu',30),
('Rule_05','Rao',35)

Select * from @Table

当前结果集

Rule_ID名称年龄

Rule_01 Mohan   29
Rule_01 Manasa  25
Rule_03 Raju    29
Rule_03 Miju    25
Rule_05 Ramu    30
Rule_05 Rao 35

我想要这样的输出

Rule_ID名称年龄

Rule_01 Mohan   29
Rule_01 Manasa  25
Rule_02 NULL    NULL
Rule_03 Raju    29
Rule_03 Miju    25
Rule_04 NULL    NULL
Rule_05 Ramu    30
Rule_05 Rao     35

我已经从Stack溢出中尝试了很多答案。但我无法前进。建议我

Answer 1

Rule_ID上的部队。使用Rule_ID的最后两位数。

DECLARE @Table TABLE 
( Rule_ID VARCHAR(10),
  Name    VARCHAR(10),
  Age     INT
)
INSERT INTO @Table(Rule_ID,Name,Age) 
VALUES
('Rule_01','Mohan',29),
('Rule_01','Manasa',25),
('Rule_03','Raju',29),
('Rule_03','Miju',25),
('Rule_05','Ramu',30),
('Rule_05','Rao',35)

DECLARE @MaxValue INT
SELECT @MaxValue = MAX(CAST(RIGHT(Rule_ID, 2) AS INT)) from @Table

DECLARE @Id INT = 1
;WITH Tmp (Id)
AS 
(
    SELECT @Id AS Id
    UNION ALL
    SELECT Id +1 FROM Tmp
    WHERE
        Id < @MaxValue      
)

SELECT * FROM @Table
UNION ALL
SELECT 'Rule_' + RIGHT('00' + CAST(A.Id AS NVARCHAR(2)), 2), NULL, null FROM Tmp A
WHERE
    NOT EXISTS
    (
        SELECT TOP 1 1 FROM @Table T
        WHERE
            T.Rule_ID = 'Rule_' + RIGHT('00' + CAST(A.Id AS NVARCHAR(2)), 2)
    )
ORDER BY Rule_ID

生产

Rule_ID    Name       Age
---------- ---------- -----------
Rule_01    Mohan      29
Rule_01    Manasa     25
Rule_02    NULL       NULL
Rule_03    Raju       29
Rule_03    Miju       25
Rule_04    NULL       NULL
Rule_05    Ramu       30
Rule_05    Rao        35

Answer 2

获得所需结果的一种方法是，如果事先知道不同的Rule_ID（即修复）并且您没有应该存在的不同Rule_ID的来源，则使用table value constructor，如下所示：

SELECT Rules.Rule_ID, t.Name, t.Age 
FROM (
    VALUES ('Rule_01'),('Rule_02'),('Rule_03'),('Rule_04'),('Rule_05')
) AS Rules (Rule_ID)   
LEFT JOIN @Table t ON t.Rule_ID = Rules.Rule_ID

这适用于固定数据，但如果Rule_ID的范围取决于表中的数据，并且您希望填补最低和最高数字之间的差距，则另一种解决方案可能会更好。

Answer 3

SELECT tally.Rule_ID ,Name ,  Age
FROM (
    SELECT TOP(99) Rule_ID='Rule_' + left('0'+cast(row_number() over (order by (select null)) as varchar(2)), 2)
    FROM sys.all_objects ) AS tally
LEFT JOIN @Table t ON t.Rule_ID = tally.Rule_ID

如何在表数据的间隙中获取缺失值

3 个答案: