Question

我想要一个PHP脚本来读取.xml文件并显示某个特定值。所以例如我想找出＆＃34; name＆＃34;值为classname＆＃34; Jack-User2＆＃34;。我希望它能展示杰克＆＃34;。或者，如果我想显示＆＃34; John-User1＆＃34;的类名的姓氏？它会显示＆＃34;亨利＆＃34;。

我已经尝试过搜索一下，并且找不到我需要的东西也没有多少运气。我发现了你发送订单号的那些。但我希望能够设置一个特定的值并让它找到。

我想要的大概是这样的：

<?php
$classname = "John-User1";
$xml = simplexml_load_file('myfile.xml');

echo $name; //I want the name that is for John-User1 to appear here
echo $lastname; //I want the last name here.
?>

我的XML文件：

<customerdata>
    <infotype>
        <usertype id="1" classname="John-User1">
            <revision_id>1223</revision_id>
            <firstname>John</name>
            <lastname>Henry</lastname>
        </usertype>
        <usertype id="2" classname="Jack-User2">
            <revision_id>1223</revision_id>
            <name>Jack</name>
            <lastname>Thompson</lastname>
        </usertype>
        <usertype id="3" classname="Brad-User3">
            <revision_id>1223</revision_id>
            <name>Brad</name>
            <lastname>Henry</lastname>
        </usertype>
        <usertype id="4" classname="Jane-User4">
            <revision_id>1223</revision_id>
            <name>Jane</name>
            <lastname>Harrison</lastname>
        </usertype>
    </infotype>
</customdata>

如果有人可以帮助这个小项目，我真的很感激。感谢

Answer 1

您的XML文件中有2个错误

<name>John</name>至</customdata>

和</customerdata>到$classname = "John-User1"; //Read the XML file $xmlContent = file_get_contents("txt.xml"); //Convert XML file to an object $xmlObjects = simplexml_load_string($xmlContent); //Create variables $name; $lastname; foreach ($xmlObjects->infotype->usertype as $user) { //Check if names are equal if ($user["classname"] == $classname) { $name = $user->name; $lastname = $user->lastname; } } echo $name; echo "<br>"; echo $lastname;

下面的代码应该适合你。

John
Henry

输出：

{{1}}

PHP读取xml并显示特定值

1 个答案: