如何在Apache-CXF客户端中调用上传文件中发送multipart / formData?

时间:2016-07-22 07:01:38

标签: java apache web-services cxf http-status-code-401

您好我正在我的项目中使用upload api。我能够使用jersy客户端发送数据并获得响应。

我得到200作为回应。这是代码。

    final Client client = ClientBuilder.newBuilder().register(MultiPartFeature.class).build();
    client.register(new LoggingFilter());
    FileDataBodyPart filePart = new FileDataBodyPart("file", new File("/Users/rasaminathan/Desktop/test.txt"));
    FormDataMultiPart formDataMultiPart = new FormDataMultiPart();
    FormDataMultiPart multipart = (FormDataMultiPart) formDataMultiPart.field("param1", "paramValue")
                                                .field("param2", "value")
                                                .bodyPart(filePart);   
    final WebTarget target = client.target("http://URL:8000/apiPath");
    final Response response = target.request().post(Entity.entity(multipart, multipart.getMediaType()));

这是我得到的日志。

    Jul 22, 2016 12:15:14 PM org.glassfish.jersey.filter.LoggingFilter log
    INFO: 1 * Sending client request on thread main
    1 > POST http://URL:8000/apiPath
    1 > Content-Type: multipart/form-data

    Jul 22, 2016 12:15:15 PM org.glassfish.jersey.filter.LoggingFilter log
    INFO: 1 * Client response received on thread main
    1 < 200
    1 < Content-Length: 203
    1 < Content-Type: application/json
    1 < Date: Fri, 22 Jul 2016 06:45:14 GMT
    1 < X-Powered-By: Servlet/2.5 JSP/2.1

但在我的项目中我们应该使用CXF。我尝试使用CXF webclient。但我得到“401”未经授权的错误。 这是代码。

    WebClient client = WebClient.create("http://URL:8000");
    String path = "apiPath"; 
    client.type(MediaType.MULTIPART_FORM_DATA)
            .path(path);

    ClientConfiguration config = WebClient.getConfig(client);
    config.getInInterceptors().add(new LoggingInInterceptor());
    config.getOutInterceptors().add(new LoggingOutInterceptor());

    List<Attachment> atts = new LinkedList<Attachment>();
    atts.add(new Attachment("file", "application/octet-stream", new ByteArrayInputStream("testContent".getBytes())));
    atts.add(new Attachment("param1","text/plain","paramValue"));
    atts.add(new Attachment("param2","text/plain","value"));
    MultipartBody body = new MultipartBody(atts);
    Response response= client.post(body);

这是我得到的日志。

        Jul 22, 2016 12:23:41 PM org.apache.cxf.interceptor.LoggingOutInterceptor
        INFO: Outbound Message
        ---------------------------
        ID: 1
        Address: http://URL:8000/apiPath
        Http-Method: POST
        Content-Type: multipart/form-data; boundary="uuid:14597725-d376-4643-92f9-7a4a64ae1054"
        Headers: {Accept=[*/*]}
        Payload: --uuid:14597725-d376-4643-92f9-7a4a64ae1054
        Content-Type: application/octet-stream
        Content-Transfer-Encoding: binary
        Content-ID: <file>

        testContent
        --uuid:14597725-d376-4643-92f9-7a4a64ae1054
        Content-Type: text/plain
        Content-Transfer-Encoding: binary
        Content-ID: <param1>

        paramValue
        --uuid:14597725-d376-4643-92f9-7a4a64ae1054
        Content-Type: text/plain
        Content-Transfer-Encoding: binary
        Content-ID: <param2>

        value
        --------------------------------------
        Jul 22, 2016 12:23:42 PM org.apache.cxf.interceptor.LoggingInInterceptor
        INFO: Inbound Message
        ----------------------------
        ID: 1
        Response-Code: 401
        Encoding: UTF-8
        Content-Type: text/html; charset=UTF-8
        Headers: {Content-Length=[46], content-type=[text/html; charset=UTF-8], Date=[Fri, 22 Jul 2016 06:53:42 GMT], X-Powered-By=[Servlet/2.5 JSP/2.1]}
        --------------------------------------

我猜params“Param1,Param2”值没有正确发送。这就是为什么我猜错了401错误。 我是否在CXF webclient中正确发送数据?如果没有,请帮我纠正代码

1 个答案:

答案 0 :(得分:1)

在所有附件中设置内容处置有助于解决问题。我找到了解决方案 here.

正如我猜测Param1,param2值未到达服务器。

        List<Attachment> atts = new LinkedList<Attachment>();
        ContentDisposition cd = new ContentDisposition("form-data; name=\"file\";filename=\"test.txt\"");
        atts.add(new Attachment("file", new ByteArrayInputStream("testContent".getBytes()),cd));
        ContentDisposition cd1 = new ContentDisposition("form-data; name=\"param1\";");
        atts.add(new Attachment("param1",new ByteArrayInputStream("paramValue".getBytes()),cd1));
        ContentDisposition cd2 = new ContentDisposition("form-data; name=\"param2\";");
        atts.add(new Attachment("param2",new ByteArrayInputStream("value".getBytes()),cd1));
        MultipartBody body = new MultipartBody(atts);
        Response response= client.post(body);

现在我得到了成功的回应