Question

我发现void返回警报但未找到字符串警报返回。尝试Void to String

// return Void Alert
func returnAlert(title: String!, message: String! ,success: (() -> Void)? , cancel: (() -> Void)?) {
    dispatch_async(dispatch_get_main_queue(), {
        let alertController = UIAlertController(title:title,
            message: "",
            preferredStyle: UIAlertControllerStyle.Alert)

        self.newQtyField = UITextField()
        self.newQtyField.keyboardType = .NumberPad

        func addTextField(textField: UITextField!){
            // add the text field and make the result global
            let row = self.array[Int(message)!]
            textField.text = String(row.pbQty!)
            self.newQtyField = textField
        }


        let cancelLocalized = NSLocalizedString("cancel", tableName: "activity", comment:"")
        let okLocalized = NSLocalizedString("ok", tableName: "Localizable", comment:"")

        let cancelAction: UIAlertAction = UIAlertAction(title: cancelLocalized,
        style: .Cancel) {
            action -> Void in cancel?()
        }
        let successAction: UIAlertAction = UIAlertAction(title: okLocalized,
        style: .Default) {
            action -> Void in success?()
        }
        alertController.addTextFieldWithConfigurationHandler(addTextField)
        alertController.addAction(cancelAction)
        alertController.addAction(successAction)


        self.presentViewController(alertController, animated: true, completion: nil)
    })
}

//底部呼唤乐趣|我认为成功：{（）成功：{textfield，但不工作如何...需要你的帮助

    returnAlert("title", message: "msg", success: { () -> Void in


        })
    { () -> Void in
        print("user canceled")
    }

Answer 1

很难理解你在问题中所说的内容。

您应该将方法定义更改为：

func returnAlert(title: String!, message: String! ,success: ((text:String) -> Void)? , cancel: (() -> Void)?) {

并更改successAction以返回UITextField的值：

let successAction: UIAlertAction = UIAlertAction(title: okLocalized,
            style: .Default) { action in
                success?(text: self.newQtyField.text!)
            }

swift代码返回警报类型字符串不起作用

1 个答案: