我正在尝试编写一个将三个表连接在一起的postgres查询。我相信我有一切正确,但当我运行查询时,我得到一个语法错误:
select
cwd_user.id,
cwd_user.user_name username,
cwd_user.email_address emailaddress,
cwd_user.active active
cwd_user.created_date created
cwd_membership.child_id
cwd_membership.parent_name groupname
licenserolesgroup.id
licenserolesgroup.license_role_name application
from
cwd_user
inner join cwd_membership on cwd_membership.child_id = cwd_user.id
inner join licenserolesgroup on cwd_membership.child_id = licenserolesgroup.id;
查询应该能够输出:
对此有任何帮助将不胜感激。加入时我没有做太多。我猜是试着火!
答案 0 :(得分:0)
你错过了一堆尾随逗号。请尝试改为:
select
cwd_user.id,
cwd_user.user_name username,
cwd_user.email_address emailaddress,
cwd_user.active active,
cwd_user.created_date created,
cwd_membership.child_id,
cwd_membership.parent_name groupname,
licenserolesgroup.id,
licenserolesgroup.license_role_name application
from
cwd_user
inner join cwd_membership on cwd_membership.child_id = cwd_user.id
inner join licenserolesgroup on cwd_membership.child_id = licenserolesgroup.id;
答案 1 :(得分:0)
我在帖子中没有看到任何错误消息。我认为这是因为缺少','每个字段末尾的(逗号)字符?
select
cwd_user.id,
cwd_user.user_name username,
cwd_user.email_address emailaddress,
cwd_user.active active,
cwd_user.created_date created,
cwd_membership.child_id,
cwd_membership.parent_name groupname,
licenserolesgroup.id,
licenserolesgroup.license_role_name application
from
cwd_user
inner join cwd_membership on cwd_membership.child_id = cwd_user.id
inner join licenserolesgroup on cwd_membership.child_id = licenserolesgroup.id;