致命错误:在oop.php中调用null上的成员函数query()

时间:2016-07-21 21:54:56

标签: php database oop insert

我今天编写PHP脚本并收到致命错误信息,我无法在互联网上找到任何解决方案,请帮助我!

致命错误:在第23行的oop.php中调用null上的成员函数query()

<?php

class DatabaseConnection {

    public $dbconnection;
    public $dbhost;
    public $dbuser;
    public $dbpass;
    public $dbname;

// Create connection
    public function __construct($dbhost, $dbuser, $dbpass, $dbname) {
    $this->dbconnection = new mysqli($this->dbhost = $dbhost, $this->dbuser = $dbuser, $this->dbpass = $dbpass, $this->dbname = $dbname);
    }

}

class sql extends DatabaseConnection {

    public $sql;

    public function __construct($sql) {
        if ($this->dbconnection->query($this->sql=$sql) === TRUE) {
        echo "New record created successfully";
        } else {
        echo "Error: " . $this->sql . "<br>" . $this->dbconnection->error;
        }
    }

}

结束有index.php

<?php
require 'oop.php';
$mydb = new DatabaseConnection("localhost", "admin", "admin", "tutorial");

if(isset($_POST['submit'])) {

$firstname = $_POST['firstname'];
$username = $_POST['username'];
$password = $_POST['password'];

$insertdata = new sql("INSERT INTO tutorial (firstname, username, password)
VALUES ('$firstname', '$username', '$password')");
?>

<p>Firstname: <?php echo $firstname; ?></p>
<p>Username: <?php echo $username; ?></p>
<p>Password: <?php echo $password; ?></p>

<?php } ?>



<form method="post">
<input type="text" name="firstname" placeholder="Firstname"/></br>
<div style="height:10px;"></div>
<input type="text" name="username" placeholder="Username"/></br>
<div style="height:10px;"></div>
<input type="password" name="password" placeholder="Password"/></br>
<div style="height:10px;"></div>
<input type="submit" name="submit" value="Enter"/>

</form>

1 个答案:

答案 0 :(得分:0)

默认情况下,PHP不会调用祖先构造函数,因此当您实例化sql对象时,$this->dbconnection不会存在,因为Databaseconnection::__construct永远不会被调用。< / p>

您的代码应为

class sql extends databasdeconnection {
   function __construct() {
       parent::__construct(); // create dbconnection
       ... use $this->dbconnection
   }
}