Ios Swift Override双击UItextField

Question

我想在UITextField上双击编写自定义代码，并阻止键盘的默认文本编辑和弹出。我已经尝试了以下内容，到目前为止我没有任何工作。请帮我解决这个问题。

let gestureArray = NamTxtBoxVal.gestureRecognizers
var tapGesture = UITapGestureRecognizer()
for idxVar in gestureArray!
{
    if let tapVar = idxVar as? UITapGestureRecognizer
    {
        if tapVar.numberOfTapsRequired == 2
        {
            tapGesture = tapVar
            NamTxtBoxVal.removeGestureRecognizer(tapGesture)
        }
    }
}

let doubleTap = UITapGestureRecognizer(target: self, action: #selector(namFnc(_:)))
doubleTap.numberOfTapsRequired = 2
doubleTap.delegate = self
tapGesture.requireGestureRecognizerToFail(doubleTap)
NamTxtBoxVal.addGestureRecognizer(doubleTap)

我也尝试过：

func gestureRecognizer(gestureRecognizer: UIGestureRecognizer, shouldRecognizeSimultaneouslyWithGestureRecognizer otherGestureRecognizer: UIGestureRecognizer) -> Bool
{

    return false
}

Answer 1

我知道你这样做的唯一方法是

1. 将UIView放在UITextField
后面
2. 设置textField的userInteractionEnabled = false
3. 将双击手势添加到UIView

这将允许您在TextField区域注册双击，而不是弹出任何键盘或进入编辑模式。

不确定双击后你打算用textField做什么，但是你应该能够以编程方式处理大部分内容。

此代码为：

class ViewController: UIViewController {
    @IBOutlet weak var myViewBehindMyTextField: UIView!
    @IBOutlet weak var myTextField: UITextField!

    override func viewDidLoad() {
        super.viewDidLoad()
        let tapGesture = UITapGestureRecognizer(target: self, action: #selector(ViewController.myTextFieldTapped(_:)))
        tapGesture.numberOfTapsRequired = 2
        myViewBehindMyTextField.addGestureRecognizer(tapGesture)
    }

    func myTextFieldTapped(sender: UITapGestureRecognizer) {
        print("Double tapped on textField")
    }
}