Question

我要做的是创建一个语法高亮显示器。我需要帮助的是创建reg表达式来查找和突出显示punction标记，但我希望匹配排除某些字符之间的字符串“”，''并排除字符串已被评论或定义//，/ ** /，＃。我目前正在使用这种模式

'/(!|%|\^|\*|\(|\)|\+|\=|\-|&gt;|&lt;|\?|,|\.|\:|\;|\'|&amp;|\[|\]|\}|\{|~)(?=[^>]*(<|$))/'

这部分似乎可以解决标签之间的问题，但老实说它看起来不正确，我对如何正确构建模式毫无头绪。

(?=[^>]*(<|$))

这是我的精彩集锦课程

class SyntaxHighlight 
{
public static function process($s,$lang,$raw = false) 
{
    $orig_s = $s;

    $regexp = array(

          //Keywords working
        '/(?<!\w|\$|\%|\@|>)(and|or|xor|for|do|while|foreach|as|return|die|exit|if|then|else|
            elseif|new|delete|try|throw|catch|finally|class|function|string|
            array|object|resource|var|bool|boolean|int|integer|float|double|
            real|string|array|global|const|static|public|private|protected|
            published|extends|switch|true|false|null|void|this|self|struct|
            char|signed|unsigned|short|long|break|goto|static_cast|const_cast|
            LIMIT|ASC|DESC|ORDER|BY|SELECT|FROM|WHERE)(?!\w|=")/iux'
        => '<span class="K">$1</span>',

        //$var, %var, @var
        '/(?<!\w)(
            (\$|\%|\@)(\-&gt;|\w)+
        )(?!\w)/ix'
        => '<span class="V">$1</span>',

        // Numbers (also look for Hex)
        '/(?<!\w)(
            0x[\da-f]+|
            \d+
        )(?!\w)(?=[^"]*(<|"))/ix'
        => '<span class="N">$1</span>',

     //comments
    '/(\/\*.*?\*\/|
            \/\/.*?\n|
            \#.[^a-zA-Z0-9]+?\|
            \&lt;\!\-\-[\s\S]+\-\-\&gt;|
            (?<!\\\)\'(.*?)(?<!\\\)\'
        )/isx' 
    => '<span class="C">$1</span>',

    //char strings
     '/\'(.+?)\'(?=[^>]*(<|$))/'
    => "<span class='CS'>'$1'</span>",

    //back quote strings
     '/\`(.+?)\`(?=[^>]*(<|$))/'
    => "<span class='BS'>`$1`</span>",

     //strings
     '/&quot;(.+?)&quot;(?=[^>]*(<|$))/'
    => '<span class="S">"$1"</span>',

    //Punc
     '/(!|%|\^|\*|\(|\)|\+|\=|\-|&gt;|&lt;|\?|,|\.|\:|\;|\'|&amp;|\[|\]|\}|\{|~)(?=[^>]*(<|$))/'
    => '<span class="P">$1</span>',

    );

    $s = preg_replace( array_keys($regexp), array_values($regexp), $s);

     if($lang == "Text" || $lang == "Other")
     $s = $orig_s;

     if($raw == "false")
     $s = self::DisplayLineCount($s);

     return '<pre style = "background-color:white;margin:0auto;text-align:left;overflow:auto;">'.$s.'</pre>';
}

private static function DisplayLineCount($s)
{
    $i=1;
    $count = substr_count($s, "\n");

    $s = "<span style = 'color:#dfecf2;'>".$i."\t</span>".$s;

    while($i <= $count)
    {
        ++$i;
        $s = preg_replace("/[\n]/","<span style = 'color:#dfecf2;'>".$i."\t</span>",$s,1);
    }

    return $s;
}
}

我从数据库获取高亮度的语法并调用这样的函数。

if(isset($row['syntax']) && $row['syntax'] == $cat_ && isset($row['title']) && $row['title'] == $top_ && isset($row['id']) && $row['id'] == $id_)
{ 
    $id_ = isset($row['id']) ? $row['id'] : '';
    $top_ = isset($row['title']) ? $row['title'] : '';
    $top_ = htmlspecialchars($top_);
    $auth_ = isset($row['author']) ? $row['author'] : '';
    $date_ = isset($row['date']) ? $row['date'] : '';
    $post_ = isset($row['paste']) ? $row['paste'] : '';
    $newtext = htmlspecialchars($post_);
    echo SyntaxHighlight::process($newtext,$cat_,$raw);

}

我是使用reg表达式模式的新手，所以请原谅我，并提前感谢你。

如何从reg表达式中排除某些字符之间的字符

0 个答案: