我是杰克逊的新手,我有一个示例json输出需要使用jackson来获取这些数据作为响应,我已经创建了pojo类,因为我知道这种问题要通过json简单实现,但是我没有想到要用杰克逊做这件事。请一些人提供一些帮助。
这是我的样本json数据 -
{
"apmmetrics": [
{
"metric": "Somevalue",
"level": "somevalue",
"data": [
{
"host": "someValue",
"instance": "someValue",
"app": "someValue",
"series": [
{
"bucket": "201607210949",
"max": 300,
"min": 15,
"avg": 57.55,
"total": 1899,
"count": 33
},
{
"bucket": "201607210948",
"max": 437,
"min": 13,
"avg": 93.5,
"total": 13464,
"count": 144
},
{
"bucket": "201607210947",
"max": 431,
"min": 13,
"avg": 86.25,
"total": 28376,
"count": 329
}
]
}
]
}
]}
这些是我的pojo课程 -
public class MetricsCollection {
private String metric;
private String level;
private List<MetricsGroup> data;
private transient Map<String, MetricsGroup> meta;
}
public class MetricsGroup {
private String host;
private String instance;
private String app;
private List<GenericMetrics> series;
private transient Map<String, GenericMetrics> metaMap;
}
public class BaseMetrics implements Serializable {
private static final long serialVersionUID = -3249688349785265214L;
protected double max = 0.0;
protected double min = 0.0;
protected double avg = 0.0;
protected double total = 0.0;
protected long count = 0;
}
public class GenericMetrics extends BaseMetrics {
private static final long serialVersionUID = -9057601499394607167L;
private String bucket;
private transient long rc = 0;
}
请让我知道如何实现这一目标。真的很感激。提前谢谢。
答案 0 :(得分:1)
您应该使用名为apmmetrics
MetricsCollection
的属性数组创建另一个类(rootPojo)。
然后生成json:mapper.writeValueAsString(rootPojo);
编辑:
或者只是:
final ObjectMapper mapper = new ObjectMapper();
final Map<String, List<MetricsCollection>> dataMap = ...
dataMap.put("apmmetrics", listOfMetricsCollection);
System.out.println(mapper.writeValueAsString(dataMap));