Question

我想使用Sqoop将数据从Oracle数据库导入Hive。我希望Sqoop将表创建到目标Hive数据库中。

我将Oracle JDBC（ojdbc6.jar）放入Sqoop lib目录。

我尝试了这两种方法，但都没有。

sqoop import \
    --connect jdbc:oracle:thin:@${DB_HOST}:${DB_PORT}:${DB_NAME} \
    --username ${DB_USER} \
    --password ${DB_PWD} \
    --table ${INPUT_TABLE} \
    --hcatalog-home /usr/hdp/current/hive-webhcat \
    --hcatalog-database ${OUTPUT_DB} \
    --hcatalog-table ${OUTPUT_TABLE} \
    --create-hcatalog-table \
    --num-mappers 1


sqoop import  \
    --connect jdbc:oracle:thin:@${DB_HOST}:${DB_PORT}:${DB_NAME} \
    --username ${DB_USER} \
    --password ${DB_PWD} \
    --hive-home /usr/hdp/current/hive \
    --hive-import \
    --create-hive-table \
    --hive-table "${OUTPUT_DB}.${OUTPUT_TABLE}" \
    --table ${INPUT_TABLE}

我有以下错误消息：

错误工具.ImportTool：导入失败：找不到列目标表input_table。请确保您的表名是正确的。

似乎Sqoop没有考虑到--create-hcatalog-table或--create-hive-table

但是，当我使用Sqoop从PostgreSQL导入数据时，表创建效果很好。有任何想法吗？感谢

有关信息，Sqoop很好地阅读了Oracle表。我运行了这个命令，得到了很好的结果：

sqoop eval \
    --connect jdbc:oracle:thin:@${DB_HOST}:${DB_PORT}:${DB_NAME} \
    --username ${DB_USER} \
    --password ${DB_PWD} \
    --query "select count(1) from input_table"

我的错误的完整日志：

16/07/21 18:08:29 INFO sqoop.Sqoop: Running Sqoop version: 1.4.6.2.4.0.0-169
16/07/21 18:08:29 DEBUG tool.BaseSqoopTool: Enabled debug logging.
16/07/21 18:08:29 WARN tool.BaseSqoopTool: Setting your password on the command-line is insecure. Consider using -P instead.
16/07/21 18:08:29 INFO tool.BaseSqoopTool: Using Hive-specific delimiters for output. You can override
16/07/21 18:08:29 INFO tool.BaseSqoopTool: delimiters with --fields-terminated-by, etc.
16/07/21 18:08:29 DEBUG sqoop.ConnFactory: Loaded manager factory: org.apache.sqoop.manager.oracle.OraOopManagerFactory
16/07/21 18:08:29 DEBUG sqoop.ConnFactory: Loaded manager factory: com.cloudera.sqoop.manager.DefaultManagerFactory
16/07/21 18:08:29 DEBUG sqoop.ConnFactory: Trying ManagerFactory: org.apache.sqoop.manager.oracle.OraOopManagerFactory
16/07/21 18:08:29 DEBUG oracle.OraOopManagerFactory: Data Connector for Oracle and Hadoop can be called by Sqoop!
16/07/21 18:08:29 INFO oracle.OraOopManagerFactory: Data Connector for Oracle and Hadoop is disabled.
16/07/21 18:08:29 DEBUG sqoop.ConnFactory: Trying ManagerFactory: com.cloudera.sqoop.manager.DefaultManagerFactory
16/07/21 18:08:29 DEBUG manager.DefaultManagerFactory: Trying with scheme: jdbc:oracle:thin:@host:1521:sid
16/07/21 18:08:29 DEBUG manager.OracleManager$ConnCache: Instantiated new connection cache.
16/07/21 18:08:29 INFO manager.SqlManager: Using default fetchSize of 1000
16/07/21 18:08:29 DEBUG sqoop.ConnFactory: Instantiated ConnManager org.apache.sqoop.manager.OracleManager@7d8704ef
16/07/21 18:08:29 INFO tool.CodeGenTool: Beginning code generation
16/07/21 18:08:29 DEBUG manager.OracleManager: Using column names query: SELECT t.* FROM input_table t WHERE 1=0
16/07/21 18:08:29 DEBUG manager.SqlManager: Execute getColumnInfoRawQuery : SELECT t.* FROM input_table t WHERE 1=0
SLF4J: Class path contains multiple SLF4J bindings.
SLF4J: Found binding in [jar:file:/usr/hdp/2.4.0.0-169/hadoop/lib/slf4j-log4j12-1.7.10.jar!/org/slf4j/impl/StaticLoggerBinder.class]
SLF4J: Found binding in [jar:file:/usr/hdp/2.4.0.0-169/zookeeper/lib/slf4j-log4j12-1.6.1.jar!/org/slf4j/impl/StaticLoggerBinder.class]
SLF4J: See http://www.slf4j.org/codes.html#multiple_bindings for an explanation.
SLF4J: Actual binding is of type [org.slf4j.impl.Log4jLoggerFactory]
16/07/21 18:08:30 DEBUG manager.OracleManager: Creating a new connection for jdbc:oracle:thin:@host:1521:sid/user, using username: user
16/07/21 18:08:30 DEBUG manager.OracleManager: No connection paramenters specified. Using regular API for making connection.
16/07/21 18:08:30 INFO manager.OracleManager: Time zone has been set to GMT
16/07/21 18:08:30 DEBUG manager.SqlManager: Using fetchSize for next query: 1000
16/07/21 18:08:30 INFO manager.SqlManager: Executing SQL statement: SELECT t.* FROM input_table t WHERE 1=0
16/07/21 18:08:30 DEBUG manager.SqlManager: Found column c1 of type [2, 10, 0]
16/07/21 18:08:30 DEBUG manager.SqlManager: Found column c2 of type [2, 10, 0]
16/07/21 18:08:30 DEBUG manager.SqlManager: Found column c3 of type [12, 20, 0]
16/07/21 18:08:30 DEBUG manager.SqlManager: Found column c4 of type [2, 0, -127]
16/07/21 18:08:30 DEBUG manager.SqlManager: Found column c5 of type [2, 0, -127]
16/07/21 18:08:30 DEBUG manager.SqlManager: Found column c6 of type [12, 80, 0]
16/07/21 18:08:30 DEBUG manager.SqlManager: Found column c7 of type [93, 0, 0]
16/07/21 18:08:30 DEBUG manager.SqlManager: Found column c8 of type [12, 20, 0]
16/07/21 18:08:30 DEBUG manager.OracleManager$ConnCache: Caching released connection for jdbc:oracle:thin:@host:1521:sid/user
16/07/21 18:08:30 ERROR tool.ImportTool: Imported Failed: There is no column found in the target table intput_table. Please ensure that your table name is correct.

Answer 1

我找到了一个解决方案，似乎--table参数对我来说效果不好，所以我习惯用--query参数代替。

    sqoop import \
        --connect ${DB_CNX_STR} \
        --username ${DB_USER} \
        --password ${DB_PWD} \
        --query "SELECT * FROM ${INPUT_TABLE} WHERE \$CONDITIONS" \
        --target-dir ${TARGET_DIR}/${INPUT_TABLE} \
        --hive-import \
        --hive-home "/usr/hdp/current/hive" \
        --create-hive-table \
        --hive-table "${OUTPUT_DB}.${OUTPUT_TABLE}" \
        --num-mappers 1

Sqoop Oracle Import不会创建表

1 个答案: