我想这样做:
uint8_t **t;
int i;
int m[100];
int i;
t = calloc(n, sizeof(uint8*));
...
/* m is initialized in other function */
...
for (i=0;i<n;i++)
{
/* m[i] is calculated here */
*t = calloc(1, sizeof(uint8)*m[i]);
}
我想转换此行为
byte [][]t;
int i;
int[] m = new int [100];
...
/* m is initialized in other function */
...
t = new byte[n];
for (i=0;i<n;i++)
{
/* m[i] is calculated here */
t[i] = new byte[m[i]];
}
这样做是否正确
答案 0 :(得分:1)
列表可能适合您吗?然后你可以根据需要构建一个字节数组并添加到整个List集合对象中?
List<byte[]> myByteList = new List<byte[]>();
for (whatever loop )
{
byte[] justOne = however you build one byte array;
myByteList.Add( justOne );
}
然后你可以稍后迭代它......
foreach( byte[] oneByteArray in myByteList )
{
do something with the oneByteArray;
}