查询表的结果
SELECT cc.Contact_ID
, SUM(HeadCount)
, c.ClientID
, c.Client_Name
, cc.Contact_Name
, cc.Role
, cs.Communication
, cs.ResponseTime
, cs.LeadershipStyle
, cs.Trust
, cs.Sentiment
FROM client c
LEFT
JOIN client_contact cc
ON c.ClientID = cc.Client_ID
JOIN process p
ON c.ClientID = p.ClientID
AND cc.Contact_Process = p.ProcessID
JOIN verticals v
ON v.VerticalID = cc.Contact_Vertical
LEFT
JOIN client_sentimental_indicator cs
ON cs.ClientContactID = cc.Contact_ID
WHERE c.STATUS = 1
AND p.ProcessStatus = 0
AND cc.status = 0
GROUP
BY c.ClientID
, cc.Contact_ID
ORDER
BY c.client_Name
这是表格结果
ID Sum(headcount) CID CName contname
339 6 340 xxx Inc Andy Stetson
340 3 340 xxx Danielle du Toit
351 3 322 yyy Ron Mahulkar
350 3 322 zzz Nicholas Ho
349 3 322 zzz Will Power
271 74 102 vvv Carie Hinton
338 31 102 vvv Linda Dunn
283 9 102 vvv Waseem Khan
我需要结果如下
ID Sum(headcount) exactSum CID CName contname
339 6 9 340 xxx Inc Andy Stetson
340 3 340 xxx Danielle du Toit
351 3 3 322 yyy Ron Mahulkar
350 3 322 zzz Nicholas Ho
349 3 322 zzz Will Power
271 74 114 102 vvv Carie Hinton
338 31 102 vvv Linda Dunn
283 9 102 vvv Waseem Khan
我有CID重复,需要重复显示,总和应该根据CID
完成请帮帮忙
答案 0 :(得分:0)
SELECT cid
, MIN(id)
, SUM(subtotal
FROM
( SELECT cc.Contact_ID
, SUM(HeadCount) subtotal
, c.ClientID
, c.Client_Name
, cc.Contact_Name
, cc.Role
, cs.Communication
, cs.ResponseTime
, cs.LeadershipStyle
, cs.Trust
, cs.Sentiment
FROM client c
LEFT
JOIN client_contact cc
ON c.ClientID = cc.Client_ID
JOIN process p
ON c.ClientID = p.ClientID
AND cc.Contact_Process = p.ProcessID
JOIN verticals v
ON v.VerticalID = cc.Contact_Vertical
LEFT
JOIN client_sentimental_indicator cs
ON cs.ClientContactID = cc.Contact_ID
WHERE c.STATUS = 1
AND p.ProcessStatus = 0
AND cc.status = 0
GROUP
BY c.ClientID
, cc.Contact_ID
) a
GROUP
BY cid;