Question

我尝试仅从basename和$member1的网址的$member2创建数组，依此类推到$member(n)。

基本数组i使用这样的原因，因为我将它用于另一个foreach循环。

所以这个计划看起来像这样：

$member1 = 'http://www.bla-bla.com/aFolder/anotherFolder';
$member2 = 'http://www.yada-yada.com/yetAnotherFolder/innerFolder';
$member3 = 'http://www.boo-boo.com/abcs/folder';

//this is the main array
$teams = array(
    array("url" => $member1, "selector" => "a"),
    array("url" => $member2, "selector" => "input"),
    array("url" => $member3, "selector" => "h1"),...,...);

我想构建一个foreach，最后会创建一个值为basename($member(n))的数组。

我希望我的结果看起来像这样：

Array
(
    [0] => anotherFolder
    [1] => innerFolder
    [2] => folder
)

到目前为止，我已尝试过不同的方法来提取特定值但无济于事，我无法找到如何提取特定值的方法。我很感激你的帮助。

Answer 1

$basenames = [];
foreach ($teams as $team) {
    $basenames[] = basename($team['url']);
}

Answer 2

如果我理解你的话，试试这个：

$resArray = array();

foreach($teams as $team){
    $resArray[] = basename($team['url']);
}

Answer 3

使用array_map和basename函数的解决方案：

...
$result = array_map(function($v){ return basename($v['url']); }, $teams);

Answer 4

$array = array();

foreach($teams as $team){
        $array[] = basename($team["url"]);
}
print_r($array);

将打印

Array
(
    [0] => anotherFolder
    [1] => innerFolder
    [2] => folder
)

如何只选择和打印嵌套数组的值？

5 个答案: