Question

当我尝试在ruby（或http://json.parser.online.fr/）中解析以下JSON时，我收到错误，但我无法弄清楚原因。

要解析的JSON：

"{\"RED\"=>{\"t1\"=>0, \"t2\"=>2},
  \"DANGEROUS_SITUATION\"=>{\"t1\"=>28, \"t2\"=>33},
  \"SUB\"=>{\"t1\"=>1, \"t2\"=>0}, \"RED_CARS\"=>{\"t1\"=>0, \"t2\"=>0},
  \"CRASH\"=>{\"t1\"=>10, \"t2\"=>6}, \"TRICKS\"=>{\"t1\"=>2,
  \"t2\"=>3}, \"FREE_TRIES\"=>{\"t1\"=>9, \"t2\"=>5},
  \"OWNERS\"=>{\"t1\"=>48, \"t2\"=>52}, \"ERRORS\"=>{\"t1\"=>5,
  \"t2\"=>9}, \"YELLOW_CARS\"=>{\"t1\"=>0, \"t2\"=>0},
  \"FANS\"=>{\"t1\"=>40, \"t2\"=>41}}"

编辑：如下面所述，这不是Json，而是一个字符串化的Ruby哈希，有没有办法将其转换为Ruby哈希？

Answer 1

你这样做的最安全的方法是为火星gsub火箭然后解析字符串，即。

stringified_hash = "{\"RED\"=>{\"t1\"=>0, \"t2\"=>2}, \"DANGEROUS_SITUATION\"=>{\"t1\"=>28, \"t2\"=>33}, \"SUB\"=>{\"t1\"=>1, \"t2\"=>0}, \"RED_CARS\"=>{\"t1\"=>0, \"t2\"=>0}, \"CRASH\"=>{\"t1\"=>10, \"t2\"=>6}, \"TRICKS\"=>{\"t1\"=>2, \"t2\"=>3}, \"FREE_TRIES\"=>{\"t1\"=>9, \"t2\"=>5}, \"OWNERS\"=>{\"t1\"=>48, \"t2\"=>52}, \"ERRORS\"=>{\"t1\"=>5, \"t2\"=>9}, \"YELLOW_CARS\"=>{\"t1\"=>0, \"t2\"=>0}, \"FANS\"=>{\"t1\"=>40, \"t2\"=>41}}"
JSON.parse(stringified_hash.gsub('=>', ':')

你也可以eval将stringified_hash返回给Hash，然后调用.to_json，但如果字符串中有任何可评估的代码，则可以攻击

json = eval("{\"RED\"=>{\"t1\"=>0, \"t2\"=>2}, \"DANGEROUS_SITUATION\"=>{\"t1\"=>28, \"t2\"=>33}, \"SUB\"=>{\"t1\"=>1, \"t2\"=>0}, \"RED_CARS\"=>{\"t1\"=>0, \"t2\"=>0}, \"CRASH\"=>{\"t1\"=>10, \"t2\"=>6}, \"TRICKS\"=>{\"t1\"=>2, \"t2\"=>3}, \"FREE_TRIES\"=>{\"t1\"=>9, \"t2\"=>5}, \"OWNERS\"=>{\"t1\"=>48, \"t2\"=>52}, \"ERRORS\"=>{\"t1\"=>5, \"t2\"=>9}, \"YELLOW_CARS\"=>{\"t1\"=>0, \"t2\"=>0}, \"FANS\"=>{\"t1\"=>40, \"t2\"=>41}}").to_json

Answer 2

预期的Json格式非常类似：

{
 "RED":{"t1":0, "t2":2}, 
 "DANGEROUS_SITUATION":{"t1":28, "t2":33}, 
 "SUB":{"t1":1, "t2":0}, 
 "RED_CARS":{"t1":0, "t2":0}
}

解析JSON会返回错误，而JSON似乎没问题

2 个答案: