Question

贷款（列：id，用户）
payback（columns：id，installment，scheduleDate）

如果要分12期支付贷款，那么有12笔贷款ID的回报记录。

我想了解一下用户有一个scheduleDate，他们所有回报的总和都大于2000.

SELECT user 
FROM {loans} ka 
WHERE 
(
   SELECT MAX(inst) FROM 
   (
        SELECT SUM(installment) AS inst 
        FROM {payback} 
        WHERE id IN 
        (
            SELECT id 
            FROM {loans} 
            WHERE user = ka.user
        )  
   GROUP BY scheduleDate
   ) as t1 LIMIT 0,1
) > 2000

我收到错误： 'where子句'中的未知列'ka.user'

Answer 1

这是否按要求工作？它假设，payback.id是一个引用loads.id的外键。

SELECT
  user, scheduleDate, sumInstallments
FROM
(
    SELECT
      l.user, pb.scheduleDate, SUM(pb.installment) AS sumInstallments
    FROM
      payback AS pb
    JOIN
      loans AS l
    ON
      l.id = pb.id
    GROUP BY
      l.user, pb.scheduleDate
) AS tempId
WHERE
  sumInstallments > 2000

Mysql子查询问题

1 个答案: