Question

我在应用程序的初始加载时一直收到此错误。我已经搜索了高低，我发现唯一能做的就是下面的代码。

    <?php
date_default_timezone_set("Asia/Dhaka");
if(!isset($_REQUEST['month'])){$month = date("m");}else{$month = $_REQUEST['month'];}
if(!isset($_REQUEST['year'])){$year = date("Y");}else{$year = $_REQUEST['year'];}
if(!isset($_REQUEST['day'])){$day = date('d');}else{$day = $_REQUEST['day'];}   
$timestamp = mktime (0, 0, 0, $month, 1, $year);
$monthName = date("F", $timestamp);
$prev_year = $year;
$next_year = $year;
$prev_month = $month-1;
$next_month = $month+1;
if($prev_month == 0 ){$prev_month = 12;$prev_year = $year - 1;}
if($next_month == 13 ){$next_month = 1;$next_year = $year + 1;}
$prev_month = str_pad($prev_month, 2, '0', STR_PAD_LEFT);
$next_month = str_pad($next_month, 2, '0', STR_PAD_LEFT);
?>

<div class="table">
<div class="tr caption">
<div class="th L"><a href="blog?month=<?php echo($prev_month.'&amp;year='.$prev_year);?>">&lsaquo;</a></div>
<div class="th monyer"><?php echo($monthName.'-'.$year); ?></div>
<div class='th R'><a href="blog?month=<?php echo($next_month); ?>&amp;year=<?php echo($next_year);?>">&rsaquo;</a></div>
</div>

<div class='thead'>
<div class="td">S</div>
<div class="td">M</div>
<div class="td">T</div>
<div class="td">W</div>
<div class="td">T</div>
<div class="td">F</div>
<div class="td">S</div>
</div>

<?php
$monthstart = date("w", $timestamp);
$lastday = date("d", mktime (0, 0, 0, $month + 1, 0, $year));
$startdate = -$monthstart;
//Figure out how many rows we need.
$numrows = ceil (((date("t",mktime (0, 0, 0, $month + 1, 0, $year))
+ $monthstart) / 7));
//Let's make an appropriate number of rows...
for ($k = 1; $k <= $numrows; $k++){
?><div class="tr days"><?php
//Use 7 columns (for 7 days)...
for ($i = 0; $i < 7; $i++){
$startdate++;
$startdate = str_pad($startdate, 2, '0', STR_PAD_LEFT); //Make dates leading zero
if ($startdate <= 0){
//If we have a blank day in the calendar.
?>

<div class="td L"><?php echo("&nbsp;");?></div>
<?php }elseif($startdate > $lastday){echo('<div class="td R">&nbsp;</div>');}else {
if ($startdate == date("d") && $month == date("m") && $year == date("Y")){?>
<div class="td today"><?php echo($startdate); ?></div><?php
} else { ?>
<?php if(in_array($year.'-'.$month.'-'.$startdate, $dates)) { ?>
<div class="td days"><a href="blog/archives/<?php echo($year.'-'.$month.'-'.$startdate); ?>"><?php echo($startdate); ?></a></div>
<?php }else{ ?><div class="td days"><?php echo($startdate); ?></div><?php }?>   
<?php } } } ?></div><?php } ?>
</div>

我在OnModelCreating方法中有这个设置，但它仍然抛出以下错误：

System.Data.SqlClient.SqlException：无效的对象名称＆＃39; dbo.EdmMetadata＆＃39 ;. System.Data.Entity.Core.EntityCommandExecutionException：错误执行命令定义时发生。看到内心细节例外。

Answer 1

您应该在Context类的构造函数中添加此代码。

无效的对象名称＆＃39; dbo.EdmMetadata＆＃39;

1 个答案: