Question

我正在使用两个名为Transactions和Items的表。请参阅下文

表1：交易

C_ID - State - Time
1   Start 2016-07-13 16:02:42
1   Passed  2016-07-13 20:28:21
2   Passed  2016-07-11 17:39:13
3   Passed  2016-07-07 20:23:00
4   Start   2016-07-01 13:19:54
4   Passed  2016-07-01 17:37:41
5   Start   2016-07-07 16:16:21
5   Passed  2016-07-07 21:04:01
6   Passed  2016-07-07 21:11:39
7   Passed  2016-07-08 20:30:46

表2：项目

C_No - C_ID
C1 - 5
C2 - 3
C3 - 9
C4 - 7
C5 - 6
C6 - 8
C7 - 2
C8 - 4
C9 - 10
C10 - 1

我想加入这些表并需要输出如下所述;

输出

C_No - State - Time
C10 - Start 2016-07-13 16:02:42
C10 - Passed    2016-07-13 20:28:21
C8 - Start  2016-07-01 13:19:54
C8 - Passed 2016-07-01 17:37:41
C1 - Start  2016-07-07 16:16:21
C1 - Passed 2016-07-07 20:00:01

除了连接两个表，我想要一个State和Time的过滤器。条件是（州=＆＃39;开始＆＃39;和时间＆lt; = 17:00）和（州=＆＃39;通过＆＃39;和时间＆lt; = 21:00）

我不希望任何项目都没有“开始”和“通过”。

我使用了以下查询

{SELECT distinct(c.C_No), p.State, p.Time FROM Items c
inner join Transitions p on p.c_id = c.c_id  and date(p.Time) between '2016-07-01' and CURRENT_DATE() 
and ((p.State = 'Start' and time(p.Time) <= '17:00:00') or p.State = 'Passed' )
order by c.C_No, State;}

SQLFiddle已添加到问题中。

Answer 1

试试这句话

从transactions.c_id = items.c_id中的事务内连接项中选择c_no，state，time其中（state ='Start'和right（time，8）＆lt; ='17:00:00'）或（state ='通过'和右（时间，8）＆lt; ='21:00:00'）

Answer 2

想法如下：

with t_start as (
    select t2.c_no, t1.state, t1.time
    from transactions t1 
    inner join items t2 on t2.c_id=t1.c_id
    where t1.state='State' and time(t1.time)<='17:00:00'
) t_passed as(
    select t2.c_no, t1.state, t1.time
    from transactions t1 
    inner join items t2 on t2.c_id=t1.c_id
    where t1.state='Passed' and time(t1.time)<='21:00:00'
) t_total as(
    select * from t_start
    union
    select * from t_passed
)
select * from t_total order by c_no, state;

Answer 3

在您的问题中，对于您的示例数据，我认为结果中不应存在C1，因为当C_ID = 5时，其State为'已通过'且其Time是'2016-07-07 21:04:01'，它与您的情况不符。所以试试这个：

select t2.C_No, t.`State`, t.`Time`
from Transactions t
join (
    select C_ID
    from Transactions
    where (State = 'Start' and time(`Time`) <= '17:00:00')
    or (State = 'Passed' and time(`Time`) <= '21:00:00')
    group by C_ID
    having count(distinct State) > 1
) t1 on t.C_ID = t1.C_ID
left join Items t2 on t1.C_ID = t2.C_ID
order by t2.C_No, t.`State`;

SqlFiddle Demo

MySQL内部联合和多个条件

3 个答案: