将列表转换为python中的变量

Question

我正在尝试阅读csv文件并在其中进行搜索。

我想找到一种将CSV文件中的标题用作变量的方法。这可能吗？

with open("Server.csv", newline='', encoding='utf-8', errors='ignore') as f :
    reader = csv.reader(f)
    Header = next(reader)

    # This part below is to get the Header on the file.            
    Header_array = []   
    for n in range(len(Header)):
        header_list = Header[n].replace(" ", "_")
        Header_array.append(header_list)
        print(Header_array) # this give me a list 

我想要提取的变量是

Application_Name, Environment, server_hostname, OverallStatus, Migration_Date

如何根据以下代码使用此标头作为动态变量？假设我明天在csv文件中添加“Time”，我不需要关心在下面添加Time = row [x：x] [x]。

    for row in reader :
        Application_Name            = row[0:1][0]
        Environment                 = row[1:2][0]
        server_hostname         = row[2:3][0]
        OverallStatus          = row[3:4][0]
        Migration_Date              = row[4:5][0]



        return Application_Name, server_hostname