Question

我创建了一个spring boot webservice（provider）应用程序。我正在请求中传递timewait选项。如果timewait = n的值，我必须将响应编程延迟那么多时间，即n秒/毫秒。有没有办法可以做到这一点。 XSD给出如下：

<xs:element name="asyncServerRequest">
    <xs:complexType>
        <xs:sequence>
            <xs:element name="header" type="xs:string"/>
            <xs:element name="BSID" type="xs:string"></xs:element>
            <xs:element name="encodedString" type="xs:string"></xs:element>
            <xs:element name="timewait" type="xs:int"></xs:element>
        </xs:sequence>
    </xs:complexType>
</xs:element>

<xs:element name="asyncServerResponse">
    <xs:complexType>
        <xs:sequence>
            <xs:element name="responsecode" type="xs:int"/>
            <xs:element name="reponsemessage" type="xs:string"/>
        </xs:sequence>
    </xs:complexType>
</xs:element>

Answer 1

您可以使用Thread.sleep(n)。

我认为＆＃34; n＆＃34;值以秒为单位。

            Integer seconds = n;

            try {
                Thread.sleep(seconds*1000);
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }


 //return your response here

如果你想集中这个＆＃34;延迟＆＃34;代码，然后您可以创建一个 DelayFilter ，如下所示。

import java.io.IOException;

import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class DelayFilter implements Filter {



 private static final String DELAY_PARAMETER = "n";


    public void destroy() {
        // TODO Auto-generated method stub

    }

    public void doFilter(ServletRequest req, ServletResponse resp,
            FilterChain chain) throws IOException, ServletException {

        HttpServletRequest request = (HttpServletRequest) req;

        //get delay value (DELAY_PARAMETER or n) from your request
        String delay = request.getParameter(DELAY_PARAMETER);

    if (delay!=null && !"".equals(delay)) {
        Integer seconds = Integer.valueOf(delay);

            try {
                Thread.sleep(seconds*1000);
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
}



        HttpServletResponse response = (HttpServletResponse) resp;
        response.setHeader("Cache-Control", "no-cache, must-revalidate");
        chain.doFilter(req, resp);


    }

    public void init(FilterConfig arg0) throws ServletException {
        // TODO Auto-generated method stub

    }

}

Spring Boot - 为要显示的SOAP响应添加延迟

1 个答案: