Question

我有以下csv

Date,Stage,Count,Time,Index
20151231,4,3,9:45:3991,1527.23510
20150903,4,613,12:18:0483,1605.56522

和以下代码

public List<DailyData> ReadDailyData(string dataFolder)
{
    using (var sr = new StreamReader(dataFolder))
    {
        var reader = new CsvReader(sr);
        return reader.GetRecords<DailyData>().ToList();
    }
}

public class DailyData
{
    public string Date { get; set; }
    public string Stage { get; set; }
    public string Count { get; set; }
    public string Time { get; set; }
    public string Index { get; set; }
}

转换为字符串时，CsvHelper工作正常但是，当我尝试解析DateTime时，我得到了Exception

即

public class DailyData
{
    public DateTime Date { get; set; } // should be Date obj
    public string Stage { get; set; }
    public string Count { get; set; }
    public DateTime Time { get; set; } // should be Time obj
    public string Index { get; set; }
}

我得到：＆＃34; String未被识别为有效的DateTime。＆＃34;

Answer 1

您可以使用地图类提供所需日期和时间的格式。

class DailyData
{
    public DateTime Date { get; set; } // should be Date obj
    public string Stage { get; set; }
    public string Count { get; set; }
    public DateTime Time { get; set; } // should be Time obj
    public string Index { get; set; }
}

public class DailyDataMap: ClassMap<DailyData> {
        Map(m => m.Date).TypeConverterOption.Format("yyyyMMdd");
        Map(m => m.Stage);
        Map(m => m.Count);
        Map(m => m.Time).TypeConverterOption.Format("H:mm:ffff");
        Map(m => m.Index);
}

c＃csvhelper如何解析字符串到datetime对象

1 个答案: