Question

我有一个函数（items）返回一个dict（details_dict），并希望在另一个函数（内容）中打印出这个dict。

for循环之后的details_dict的内容是：

details_dict = {
'car' : 'fast',
'bike' : 'faster',
'train' : 'slow'
 }

以下是我实施的两个功能，但我不确定它们是否正确。

def items(root):
  for a in list:   # example for loop, not important but details_dict is created here 
       details_dict = ['name' : 'state']
  return details_dict

def contents(root):
  for name, state in details_dict.items():
         print ("%s is set to %s" % (name, state)

Answer 1

您的打印声明中有一个缺少的括号和可能的缩进问题。这是您正在做的事情的修改版本，忽略了如何构建字典的详细信息：

def buildItems():
    return {
        'car': 'fast',
        'bike': 'faster',
        'train': 'slow'
    }

def contents():
    details_dict = buildItems()
    for name, state in details_dict.items():
        print ("%s is set to %s" % (name, state))

contents()

输出：

car is set to fast
train is set to slow
bike is set to faster

如果那是你想要它做的，那就有效。您可以从contents（）函数内成功打印在另一个函数中创建的dict。

Answer 2

在不知道数据结构的情况下，我做了最好的猜测。

list_a = ['car', 'bike', 'train']
list_b = ['fast', 'faster', 'slow']

def items (one, two):
    the_dict = {}
    for (i,j) in zip(one, two):
        the_dict[i] = j
    return the_dict

def contents(a_dict):
    for key in a_dict:
        print 'The key ' +key+ ' is assigned to '+a_dict[key]

details_dict = items(list_a, list_b)

contents(details_dict)

输出：

The key car is assigned to fast
The key train is assigned to slow
The key bike is assigned to faster

返回函数中的dict，然后在另一个函数中打印其内容

2 个答案: