如何在bash脚本中打印文件类型

Question

#!/bin/bash


echo "" >> "regular file"
echo "" >> "Directory file"
echo "" >> "executable file"
target="/home/personal/scripts/07_22_13/ford/$1"
for f in "$target"/*
do
    echo $(basename $f) | ls -la
    if [[ -x "$f" ]];
    then
        echo "File '$f' is executable"
    elif [[ -r "$f" ]]; 
    then
        echo "file '$f' is regular"
    else echo "file '$f' is directory"
         echo "*(-^/)"
    fi
done

代码打印具有访问权限的所有文件 我如何打印每个类型（常规，目录，可执行文件）

的文件旁边

Answer 1

if [[ -x "$file" ]]; # File is executable
if [[ -d "$file" ]]; # Is a directory

Answer 2

试试这种方式

 #!/bin/bash

 target="/path/to/target/"

 for file in `find ${target}`
 do
     stat --format=%n\ -\ %F\ -\ %A $file
     # %n prints the filename
     # %F prints the filetype
     # %A prints the permissions
     #For more info stat --help or man stat
 done