Question

我第一次尝试编写脚本。我正在尝试创建一个库存跟踪器。我在Here找到了一个很好的讨论和脚本，但我需要进行一些小修改。该脚本使用＆＃34;转储＆＃34;这将是我的＆＃34;购买＆＃34;工作簿。将项目输入转储页面时，脚本会根据＆＃34;值＆＃34;确定项目的转移位置。 col 1和col 2。

我希望在不需要条件的情况下根据项目传输数据。我目前的专栏是：日期，项目，供应商，数量，成本

来自链接的代码在

之下

＆＃13;

var fedId = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx';
var fedSheetName = 'Sheet1';
var dhlId = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx';
var dhlSheetName = 'Sheet1';
var upsId = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx';
var upsSheetName = 'Sheet1';
var dumpSheetName = 'Sheet1';
var firstColToWatch = 2;
var secondColToWatch = 1;

function onOpen() {
    var ui = SpreadsheetApp.getUi();
    ui.createMenu('Transfer')
        .addItem('Transfer rows', 'moveRows')
        .addToUi();
}


function moveRows() {


    var s = SpreadsheetApp.getActive()
        .getActiveSheet();
    var rows = [];
    var writeBack = [];
    var range = s.getDataRange();
    var val = range.getValues()
        .forEach(function (r, i) {
            if (r[1].substring(0, 3) == "DHL" && r[0] == 'Watches') { //&& is used because both conditions need to evaluate to 'true'
                  moveToSheet(dhlId, dhlSheetName, r);// Javascript arrays are zero-indexed. So r[0] is column 1...
                rows.push(i + 1);
            } else if (r[1].substring(0, 3) == "DHL" && r[0] == 'Shirts') {
                  moveToSheet(dhlId, dhlSheetName, r);
                rows.push(i + 1);
            } else if (r[1].substring(0, 3) == "UPS" && r[0] == 'Shoes')  {
                moveToSheet(upsId, upsSheetName, r);
                rows.push(i + 1);
            } else if (r[1].substring(0, 3) == "UPS" && r[0] == 'Pants')  {
                moveToSheet(upsId, upsSheetName, r);
                rows.push(i + 1);
            } else if (r[1].substring(0, 5) == "FEDEX") { //using susbstring (first 5 letters of value in col 2) so that we can match anything starting with...
                moveToSheet(fedId, fedSheetName, r);
                rows.push(i + 1);
            } else {
                writeBack.push(r);
            }
        });
    s.clear();
    s.getRange(1, 1, writeBack.length, writeBack[0].length)
        .setValues(writeBack);
}


function moveRow(e) {


    var s = e.source.getActiveSheet();
    var r = e.range.rowStart;
    if (s.getName() !== "Sheet1" || e.range.columnStart !== firstColToWatch || e.value == "") return;
    var val = s.getRange(e.range.rowStart, 1, 1, s.getLastColumn())
        .getValues()[0];
    if (e.value.indexOf("DHL") !== -1 && val[0] == "Watches") {
        moveToSheet(dhlId, dhlSheetName, val);
        s.deleteRow(r);
    } else if (e.value.indexOf("DHL") !== -1 && val[0] == "Shirts") {
        moveToSheet(dhlId, dhlSheetName, val);
        s.deleteRow(r);
    } else if (e.value.indexOf("UPS") !== -1 && val[0] == "Shoes") {
        moveToSheet(upsId, upsSheetName, val);
        s.deleteRow(r);
    } else if (e.value.indexOf("UPS") !== -1 && val[0] == "Pants") {
        moveToSheet(upsId, upsSheetName, val);
        s.deleteRow(r);
    } else if (e.value.indexOf("FEDEX") !== -1) {
        moveToSheet(fedId, fedSheetName, val);
        s.deleteRow(r);
    }


}


function moveToSheet(Id, sheetName, val) {
    var ss = SpreadsheetApp.openById(Id)
        .getSheetByName(sheetName)
        .appendRow(val);
}

＆＃13;

非常感谢任何帮助！

脚本修改将数据从一个工作表传输到另一个工作表

0 个答案: